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3 years ago

Please help me the picture is above, I will pray for you if you answer. I promise

Mathematics

1 answer:

SashulF [63]3 years ago

3 0

So with the problem the equation for answering these would be “1.50t+4=c” so to plug in the variable for t would be 0, 1, 2, 3, etc. and the variable c would be the answer of solving the equation with the plugged in number
1.50(0)+4= $4.00
1.50(1)+4= $5.50
1.50(2)+4= $7.00
1.50(3)+4= $8.50

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Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma

pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0

3 years ago

Read 2 more answers

Anty was riding his bike to school at a speed of 12 mph. When he was of the way there, he got a flat tire. His mother drove him

NemiM [27]

Complete question:

Anty was riding his bike to school at a speed of 12 mph. When he was <u>half </u>of the way there, he got a flat tire. His mother drove him the rest of the way at a speed of 48 mph. What was his average speed?

Answer:

His average speed is 19.2 mph

Step-by-step explanation:

Given;

speed of Anty to school half of the way, v₁ = 12 mph

speed of Anty when his mother drove him half of the way, v₂ = 48 mph

The average speed of Anty is calculated as;

$V_{average} = \frac{Total \ distance }{Total \ time }$

The value of the average speed is closer to 12 mph than 48 mph because Anty spent more time moving at 12 mph than at 48 mph.

Let the equal distance travel at each speed = 96 miles

Time taken at 12 mph = $\frac{96 \ mile}{12 \ m/h} = 8 \ hours$

Time taken at 12 mph = $\frac{96 \ mile}{48 \ m/h} = 2 \ hours$

Average speed = $\frac{Total \ distance}{Total \ time } = \frac{96 \ mile \ + \ 96 \ mile}{2\ hr \ + \ 8\ hr} = \frac{192 \ miles}{10 \ hrs} = 19.2 \ mph$

Also, you can assume any other equal distance traveled at each speed, the average speed will still be 19.2 mph.

<u>Check:</u> let the equal distance traveled at each speed = 480 miles

Time taken at 12 mph = 480/12 = 40 hours

Time taken at 48 mph = 480/ 48 = 10 hours

Average speed = (480 + 480) / (40 + 10)

= 19.2 mph

8 0

3 years ago

a right triangle has legs measuring 18 cm and 26 cm. What is the length of the hypotenuse? (a) 18.8 (b) 31.6 (b) 44.0 (d) 100.0

yuradex [85]

18^2+26^2= 1000

\sqrt(1000) 31.6

B 31.6

8 0

3 years ago

Which of the following shows 9x^2y - 4x + 3y^3x - 2y^2 written in standard form? A. 9x2y - 4x + 3y3x - 2y2 B. 3y3x - 2y2 + 9x2y

nlexa [21]

D. $3 y^{3}x+9 x^{2} y-2 y^{2} -4x$

Take each term and find the degree of the term and then put them in order from highest to lowest:
$y^{3}x=3+1=4$
$x^{2} y=2+1=3$
$y^{2}=2$
x=1

Remember a letter without an exponent is assumed to be a 1.

Hope that helps.

6 0

3 years ago

A room is 3 3/4 m long and 4 2/3 m wide. What is the area of the room?

ziro4ka [17]

Answer:

17.5 m

Step-by-step explanation:

3.75 x 4.667 etc.

17.5

(I used a calculator)

4 0

3 years ago