What is the potential energy of stretched spring, if the spring constant is 40 N/m and the elongation is 5 cm?

How many volts does it take to push 2 amperes of current through 20 ohms of resistance?

vodomira [7]

As we know V=IR

So, R= 20 ohms, I= 2 A

Therefore, V= 2*20 = 40 V

Electric Voltage

The difference in electric potential between two points, also known as voltage, electric potential difference, electric pressure, or electric tension, determines how much labour is required to move a test charge between the two sites in a static electric field. Volt is the name of the derived unit for voltage (potential difference) in the International System of Units. 1 volt equals 1 joule (of work) for 1 coulomb, is how to work per unit charge is stated in SI units (of charge). Power and current were utilized in the previous SI definition for the volt, and the quantum Hall and Josephson effect was incorporated in 1990. As of 2019 fundamental physical constants have been employed in the definition of all SI units and derived units.

To learn more about the electric voltage refer here:

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8 0

2 years ago

It is weigh-in time for the local under 85 kg rugby team. The bathroom scale used to assess eligibility can be described by Hook

Grace [21]

15 m/n is the answer

4 0

3 years ago

Four solid plastic cylinders all have radius 2.55 cm and length 5.70 cm. Find the charge of each cylinder given the following ad

vazorg [7]

Answer:3

Explanation:idk

5 0

3 years ago

In an experiment, a variable, position-dependent force F(x)F(x) is exerted on a block of mass 1.0kg1.0kg that is moving on a hor

leonid [27]

Answer:

The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).

(C) is correct option.

Explanation:

Given that,

Mass of block = 1.0 kg

Dependent force = F(x)

Frictional force = F(f)

Suppose, the following information would students need to test the hypothesis,

(A) The function F(x) for 0 < x < 5 and the value of F(f).

(B) The function a(t) for the time interval of travel and the value of F(f).

(C) The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).

(D) The function a(t) for the time interval of travel, the time it takes the block to move 5 m, and the value of F(f).

(E) The block's initial velocity, the time it takes the block to move 5 m, and the value of F(f).

We know that,

The work done by a force is given by,

$W=\int_{x_{0}}^{x_{f}}{F(x)\ dx}$ .....(I)

Where, $F(x)$ = net force

We know, the net force is the sum of forces.

So, $\sum{F}=ma$

According to question,

We have two forces F(x) and F(f)

So, the sum of these forces are

$F(x)+(-F(f))=ma$

Here, frictional force is negative because F(f) acts against the F(x)

Now put the value in equation (I)

$W=\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}$

We need to find the value of $\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}$

Using newton's second law

$\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{x_{0}}^{x_{f}}{ma\ dx}$ ...(II)

We know that,

Acceleration is rate of change of velocity.

$a=\dfrac{dv}{dt}$

Put the value of a in equation (II)

$\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{x_{0}}^{x_{f}}{m\dfrac{dv}{dt}dx}$

$\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{v_{0}}^{v_{f}}{mv\ dv}$

$\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\dfrac{mv_{f}^2}{2}+\dfrac{mv_{0}^2}{2}$

Now, the work done by the net force on the block is,

$W=\dfrac{mv_{f}^2}{2}+\dfrac{mv_{0}^2}{2}$

The work done by the net force on the block is equal to the change in kinetic energy of the block.

Hence, The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).

(C) is correct option.

7 0

3 years ago

In an inverse relationship which one variable increases the other?

konstantin123 [22]

Answer:

as A increases, B decreases, and as B increases, A increases. Hope this helps!

Explanation:

3 0

4 years ago