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Sindrei [870]
3 years ago
6

Cooling down after a workout allows the oxygen to continuing moving through the body and keeps the muscles from tightening up to

fast.
True

False
Physics
2 answers:
Liono4ka [1.6K]3 years ago
7 0

Answer: true

Explanation:

Strike441 [17]3 years ago
7 0

Answer:

True

Explanation:

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A stone is dropped from rest from the top of a building. It takes Δt = 2.2 s for it to reach the ground.
NeTakaya

Answer:

Value of magnitude of acceleration will be 9.8m/sec^2

Explanation:

It is given that when a stone is dropped it takes 2.2 sec to reach the ground

(a) As the stone is dropped from the top of building

So its initial velocity u_i will be 0 m /sec

(b) As the stone is free falling and there is no external force applied on it so its acceleration will be equal to acceleration due to gravity

So value of magnitude of acceleration will be equal to 9.8m/sec^2

6 0
3 years ago
Which of the following statements correctly describe the various applications listed above?
fgiga [73]

Answer:

The answer is "c,d,e, and g".

Explanation:

The correct choices can be defined as follows:

  • Higher-frequency microwaves aren't used in any of these systems.
  • Infrared waves aren't seen in each of these technologies.
  • Its shortest wavelength of all of the technologies listed is the above radiation generated by certain wireless networks.
  • These devices all produce waves of wavelengths ranging from 0.10 to 10.0 cm.
3 0
3 years ago
Consider the following reaction proceeding at 298.15 K: Cu(s)+2Ag+(aq,0.15 M)⟶Cu2+(aq, 1.14 M)+2Ag(s) If the standard reduction
lutik1710 [3]

Answer : The cell potential for this cell 0.434 V

Solution :

The balanced cell reaction will be,  

Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

Here copper (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

First we have to calculate the standard electrode potential of the cell.

E^o_{[Cu^{2+}/Cu]}=0.34V

E^o_{[Ag^{+}/Ag]}=0.80V

E^o=E^o_{[Ag^{+}/Ag]}-E^o_{[Cu^{2+}/Cu]}

E^o=0.80V-(0.34V)=0.46V

Now we have to calculate the concentration of cell potential for this cell.

Using Nernest equation :

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Cu^{2+}][Ag]^2}{[Cu][Ag^+]^2}

where,

n = number of electrons in oxidation-reduction reaction = 2

E_{cell} = ?

Now put all the given values in the above equation, we get:

E_{cell}=0.46-\frac{0.0592}{2}\log \frac{(1.14)\times (1)^2}{(1)\times (0.15)}

E_{cell}=0.434V

Therefore, the cell potential for this cell 0.434 V

8 0
3 years ago
When summer changes to fall, what seasonal changes do plants experience? (IGNORE HIGHLIGHTED ANSWER)
lorasvet [3.4K]

Answer:

C

Explanation:

There is a decrease in temperature and daylight and plants produce less food.

Please mark brainliest!!

*Quick Reminder: If this is an assignment from homeschool/school, please don't forget to rephrase/summarize/reference from this answer. Keep in mind no plagiarism is allowed in school. And please don't plagiarize this answer. Thanks!*

7 0
2 years ago
A 2.0-kilogram ball traveling north at 4.0 meters per second collides head on with a 1.0-kilogram ball traveling south at 8.0 me
enyata [817]

Answer:

We know the momentum after the collision MUST be equal to the momentum BEFORE the collision.  

Momentum is a VECTOR quantity having both magnitude and direction.  The first ball has momentum P =m*v = 2*4 = 8 at 90degrees.  The second ball has momentum P = 1*8 = 8 at -90 or 270 degrees.  They sum to zero when you perform vector addition.

Explanation:

6 0
2 years ago
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