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3 years ago

6

Cooling down after a workout allows the oxygen to continuing moving through the body and keeps the muscles from tightening up to

fast.
True

False

2 answers:

Liono4ka [1.6K]3 years ago

7 0

Answer: true

Explanation:

Strike441 [17]3 years ago

7 0

Answer:

True

Explanation:

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What is the abbreviation for mojave desert?

vagabundo [1.1K]

There is no abbreviation

3 0

3 years ago

a car takes 125 ft to brake from 60 to 0 mph. Assume that the acceleration of the Prius is constant while braking. Find how long

max2010maxim [7]

Answer:

2.84 seconds

Explanation:

t = ?

distance = 125

Velocity origianal = 60 m/hr = 88 ft/s

AVERAGE velocity = 88/2 = 44 ft/s

44 t = 125

t = 125/44 = 2.84 s

7 0

2 years ago

Some liquid is poured into a burrete so that it reads 14cm³.50 drops were run each of volume 0.1cm³ .

nika2105 [10]

Given :

Liquid is poured into a burrete so that it reads 14cm³.

50 drops were run each of volume 0.1cm³ .

To Find :

The volume of liquid in burrete after 50 drops.

Solution :

Volume of each drop, v = 0.1 cm³.

Initial volume in burrete, V = 14 cm³.

Now, volume left after droping 50 drops are :

$L = V - 50v\\\\L = 14 - 50\times 0.1 \ cm^3 \\\\L = 9 \ cm^3$

Therefore, the volume left in burrete is 9 cm³ .

5 0

3 years ago

You need a 450 microgram sample of gold, but you only have a mass balance that measures in decigrams. Convert the amount of gold

sveta [45]

The amount of gold in decigrams if 450 micrograms is needed is 4.5 × 10-³ decigrams.

<h3>How to convert micrograms to decigrams?</h3>

According to this question, 450 micrograms of a sample of gold is needed but we only have a mass balance that measures in decigrams.

This means that we are to convert the amount of gold you need to decigrams by comparing the exponents.

The conversion factor of micrograms to decigrams is as follows:

1 micrograms = 1 × 10-⁵ decigrams

This means 450 micrograms is equivalent to 450 × 1 × 10-⁵ = 4.5 × 10-³ decigrams

Therefore, the amount of gold in decigrams if 450 micrograms is needed is 4.5 × 10-³ decigrams.

Learn more about decigrams at: brainly.com/question/6869599

#SPJ1

7 0

1 year ago

A plane starting from rest (vo = 0 m/s) when t0 = 0s. The plane accelerates down the runway, and at 29 seconds, its velocity is

IrinaK [193]

Answer:

Acceleration, $a=2.48\ m/s^2$

Explanation:

Given that,

The plane is at rest initially, u = 0

Final speed of the plane, v = 72.2 m/s

Time, t = 29 s

We need to find the average acceleration for the plane. It can be calculated as :

$a=\dfrac{v-u}{t}$

$a=\dfrac{72.2}{29}$

$a=2.48\ m/s^2$

So, the average acceleration for the plane is $2.48\ m/s^2$ . Hence, this is the required solution.

4 0

3 years ago