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NemiM [27]
3 years ago
14

A body of mass 20 kg moving north with a velocity of 0.5 ms-1 is subjected to a force of 15 N North for 2.9 s. Calculate the fin

al velocity of the body.pleassse
Physics
1 answer:
bonufazy [111]3 years ago
5 0

The final velocity of the body is 2.675 m/s.

To find the final velocity of the body, we use the formula below.

<h3><u>Velocity  </u></h3>

This can be defined as the ratio of displacement to time. the S.I unit of velocity is m/s.

<u />

⇒ Formula:

  • F = m(v-u)/t.................... Equation 1

⇒ Where:

  • F = Force
  • m = mass of the body
  • v = final velocity
  • u = initial velocity
  • t = time.

⇒ make v the subject of the equation

  • v = (Ft/m)+u.................. Equation 2

From the question,

⇒ Given:

  • F = 15 N
  • m = 20 kg
  • u = 0.5 m/s
  • t = 2.9 s

⇒ Substitute these values into equation 2

  • v = [(15×2.9)/20]+0.5
  • v = 2.675 m/s

Hence, the final velocity of the body is 2.675 m/s.

Learn more about final velocity here: brainly.com/question/24815498

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A ball is thrown directly downward with an initial speed of 7.65 m/s froma height of 29.0 m. After what time interval does it st
coldgirl [10]

Answer: 1.77 s

Explanation: In order to solve this problem we have to use the kinematic equation for the position, so we have:

xf= xo+vo*t+(g*t^2)/2  we can consider the origin on the top so the xo=0 and xf=29 m; then

(g*t^2)/2+vo*t-xf=0  vo is the initail velocity, vo=7.65 m/s

then by solving the quadratric equation in t

t=1.77 s

8 0
3 years ago
6. Willingness to take turns is one way we can express our attitudes in
NNADVOKAT [17]
The answer is A ..........
5 0
3 years ago
An electron with a speed of 0.95c is emitted by a supernova, where cc is the speed of light. What is the magnitude of the moment
krok68 [10]

Answer:

2.59×10¯²² Kgm/s

Explanation:

Data obtained from the question include:

Velocity of electron = 0.95c

Momentum =?

Next, we shall determine the velocity of the electron. This can be obtained as follow:

Velocity of electron = 0.95c

Velocity of Light (c) = 3×10⁸ m/s

Velocity of electron = 0.95c

Velocity of electron = 0.95 × 3×10⁸

Velocity of electron = 2.85×10⁸ m/s

Finally, we shall determine the mometum of the electron.

Momentum is simply defined as the product of mass and velocity. Mathematically, it is expressed as:

Momentum = mass x Velocity

Thus, with the above formula, we calculate the momentum of the electron as follow:

Mass of electron = 9.1×10¯³¹ Kg

Velocity of electron = 2.85×10⁸ m/s

Momentum of electron =?

Momentum = mass x Velocity

Momentum = 9.1×10¯³¹ × 2.85×10⁸

Momentum = 2.59×10¯²² Kgm/s

Therefore, the momentum of the electron is 2.59×10¯²² Kgm/s

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4 years ago
Asbestos would most likely be found where in a house?
SCORPION-xisa [38]

Asbestos would most likely be found <u>around pipes</u> in a house.

Asbestos is nan organic naturally occurring mineral.

Its composition is similar to thin fibers like crystals of of silicate mineral.

The fibers of Asbestos are so thin and microscopic that they liberate into the atmosphere due to erosion and other processes.

These tiny particles are considered harmful for health as they are carcinogenic in nature and causes mesothelioma.

Its melting point is between 400 to 1,040 °C and is available in blue, green, grey white and yellow color.

If you need to learn more about asbestos click here:

brainly.com/question/13387975

#SPJ4

6 0
1 year ago
What kind of graph uses points on a grid connected by line segments to represent data and is usually used to show change over ti
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Line Graph

Hope this is what you are looking for! 
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