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Ierofanga [76]
2 years ago
10

How many volts does it take to push 2 amperes of current through 20 ohms of resistance?

Physics
1 answer:
vodomira [7]2 years ago
8 0

As we know V=IR

So, R= 20 ohms, I= 2 A

Therefore, V= 2*20 = 40 V

Electric Voltage

The difference in electric potential between two points, also known as voltage, electric potential difference, electric pressure, or electric tension, determines how much labour is required to move a test charge between the two sites in a static electric field. Volt is the name of the derived unit for voltage (potential difference) in the International System of Units. 1 volt equals 1 joule (of work) for 1 coulomb, is how to work per unit charge is stated in SI units (of charge). Power and current were utilized in the previous SI definition for the volt, and the quantum Hall and Josephson effect was incorporated in 1990. As of 2019 fundamental physical constants have been employed in the definition of all SI units and derived units.

To learn more about the electric voltage refer here:

brainly.com/question/14699417

#SPJ4

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For the airfoil and conditions in Problem 2.2, calculate the lift-to-drag ratio. Comment on its magnitude.
raketka [301]

Answer:

L/D= 112

Explanation:

Aerodynamics can be defined as the branch of dynamics which deals with the motion of air, their properties and the interaction between the air and solid bodies.

Aerodynamics law explains how an airplane is able to fly. There are four forces of flight, and they are; lift, weight, thrust and drag. The amount of lift generated by a wing divided by the aerodynamic drag is known as the lift to drag ratio.

Lift increases proportionally to the square of the speed.

The solutions to the question is the file attached to this explanation.

Lift,L= qC(l). S---------------------------(1).

and,

Drag,D = qC(d).S ----------------------(2).

Hence, Lift to drag ratio,L/D= C(l)/C(d).

Therefore, we have to compute various angle of attack.(check attached file)...

Then, (L/D) will then be equal to 112.

8 0
4 years ago
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Elodia [21]
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4 years ago
If a box is pushed 5.0 m across a floor using a force of 35 N, how much work was done?
aniked [119]

Answer:

175J

Explanation:

Work done is given by the product of the force applied and the distance travelled as a result of that force.

Or in formula , W=F×d

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W= 35 × 5.0=175 J or 1.8 e2 J

3 0
3 years ago
What are the parts of an atom
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Number three

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7 0
3 years ago
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How much work is required to lift a 2 kg mass to a height of 10 meters?
scoray [572]
Use the equation potential energy =m*g*h
m-mass,
g-gravitational acceleration,
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=200
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This is the unit of the energy
6 0
3 years ago
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