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1 year ago

How many volts does it take to push 2 amperes of current through 20 ohms of resistance?

Physics

1 answer:

vodomira [7]1 year ago

8 0

As we know V=IR

So, R= 20 ohms, I= 2 A

Therefore, V= 2*20 = 40 V

Electric Voltage

The difference in electric potential between two points, also known as voltage, electric potential difference, electric pressure, or electric tension, determines how much labour is required to move a test charge between the two sites in a static electric field. Volt is the name of the derived unit for voltage (potential difference) in the International System of Units. 1 volt equals 1 joule (of work) for 1 coulomb, is how to work per unit charge is stated in SI units (of charge). Power and current were utilized in the previous SI definition for the volt, and the quantum Hall and Josephson effect was incorporated in 1990. As of 2019 fundamental physical constants have been employed in the definition of all SI units and derived units.

To learn more about the electric voltage refer here:

brainly.com/question/14699417

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To solve this problem we will apply the concept of frequency in a string from the nodes, the tension, the linear density and the length of the string, that is,

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Replacing the values in the frequency and value of n is one for fundamental overtone

$f = \frac{n}{2L}(\sqrt{\frac{T}{\mu}})$

$f = \frac{1}{2(62*10^{-2})}(\sqrt{\frac{500}{(\frac{3.7*10^{-3}}{90*10^{-2}})}})$

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Similarly plug in 2 for n for first overtone and determine the value of frequency

$f = \frac{n}{2L}(\sqrt{\frac{T}{\mu}})$

$f = \frac{2}{2(62*10^{-2})}(\sqrt{\frac{500}{(\frac{3.7*10^{-3}}{90*10^{-2}})}})$

$\mathbf{f = 562.4Hz}$

Similarly plug in 3 for n for first overtone and determine the value of frequency

$f = \frac{n}{2L}(\sqrt{\frac{T}{\mu}})$

$f = \frac{3}{2(62*10^{-2})}\bigg (\sqrt{\frac{500}{(\frac{3.7*10^{-3}}{90*10^{-2}})}} \bigg)$

$\mathbf{f= 843.7Hz}$

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