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Minchanka [31]
3 years ago
12

4,3⅔,3⅓,3 common difference

Mathematics
1 answer:
Lana71 [14]3 years ago
3 0

Answer:

one third

Step-by-step explanation:

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Solve the equation by using the quadratic formula.<br> 8x2 – 2x - 15 =0
ddd [48]

Answer:

x = 3/2 or x = -5/4

Step-by-step explanation:

Solve for x over the real numbers:

8 x^2 - 2 x - 15 = 0

Using the quadratic formula, solve for x.

x = (2 ± sqrt((-2)^2 - 4×8 (-15)))/(2×8) = (2 ± sqrt(4 + 480))/16 = (2 ± sqrt(484))/16:

x = (2 + sqrt(484))/16 or x = (2 - sqrt(484))/16

Simplify radicals.

sqrt(484) = sqrt(4×121) = sqrt(2^2×11^2) = 2×11 = 22:

x = (2 + 22)/16 or x = (2 - 22)/16

Evaluate (2 + 22)/16.

(2 + 22)/16 = 24/16 = 3/2:

x = 3/2 or x = (2 - 22)/16

Evaluate (2 - 22)/16.

(2 - 22)/16 = -20/16 = -5/4:

Answer: x = 3/2 or x = -5/4

4 0
2 years ago
10. Use the data to determine the missing values in the five-number summary.
exis [7]

Answer:

Q1 - 2

Q1 - 5

Q3 - 7

maximum 9

minimum 1

Step-by-step explanation:

order the numbers from least to greatest

7 0
3 years ago
Which inverse operation would be used to verify the following equation? 54 ÷ 9 = 6        A. 9 − 6 = 3   B. 54 ÷ 6 = 9   C. 9 ×
Gnom [1K]
9 X 6 = 54. They are opposite operations
4 0
3 years ago
Read 2 more answers
A guy-wire is attached to a pole for support. If the angle of elevation to the pole is 67° and the wire is attached to the groun
Andrews [41]
The angle = 67<span>° and the pole is a right-angled triangle. Therefore the distance required to find (say "x) is the angle opposite the right-angle. The following equation needs to be solved:

cos 67 = 137 / x

Solving for x;
x = 350.62 ft</span>
3 0
3 years ago
Yo please help
Alex Ar [27]

Answer:

Options 1, 3 and 4 are true

Step-by-step explanation:

The legs EF and DF of the right triangle DEF have lengths of 24 units and 7 units, respectively. By the Pythagorean theorem,

DE^2=EF^2+DF^2\\ \\DE^2=24^2+7^2\\ \\DE^2=576+49\\ \\DE^2=625\\ \\DE=25\ units

Find trigonometric functions:

\sin \angle D=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{EF}{DE}=\dfrac{24}{25}

\cos \angle E=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}=\dfrac{EF}{DE}=\dfrac{24}{25}

\tan \angle D=\dfrac{\text{Opposite leg}}{\text{Adjacent leg}}=\dfrac{EF}{DF}=\dfrac{24}{7}

\sin \angle E=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{DF}{DE}=\dfrac{7}{25}

Thus, options 1, 3 and 4 are true

5 0
3 years ago
Read 2 more answers
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