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Rom4ik [11]
3 years ago
14

How many solutions y=10x+2 y=8x+2x+2

Mathematics
1 answer:
Wewaii [24]3 years ago
6 0

Answer:

Infinutely many solutions

Step-by-step explanation:

y = 10x + 2 --------- (1)

y = 8x +2x +2

=> y = 10x + 2---------- (2)

(1) -> 10x -y + 2 = 0

(2) -> 10x -y + 2 = 0

a1=10 ; b1=-1 ; c1 = 2

a2=10 ; b2=-1 ; c2= 2

a1/a2 = 10/10 = 1

b1/b2 = -1/-1 = 1

c1/c2 = 2/2 = 1

therefore, a1/a2 = b1/b2 = c1/c2

Therefore the line coincides and there are infinitely many solutions.

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Terri walked in her own 93rd percentile, while April swam in her own 99th percentile. April is off to a slightly better start.

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The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe
juin [17]

The height of container is 8 feet

<em><u>Solution:</u></em>

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

<em><u>The volume of container is given as:</u></em>

v = length \times width \times height

Given that volume of the container is 216 cubic feet

216 = l \times w \times h

Substitute eqn 1 and eqn 2 in above formula

216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0

Solve by factoring

(h-8)(h^2+4h+27) = 0

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

h - 8 = 0\\\\h = 8

Also,

h^2+4h+27 = 0

Solve by quadratic equation formula

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}

h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}

Therefore, on solving we get,

h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

<em><u>Thus solutions of "h" are:</u></em>

h = 8

h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

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3 years ago
On the second day of a hiking trip, the tourists covered 17% bigger distance than on the first day. By how many percent did thei
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Speed=distance/time
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Read 2 more answers
Trapezoid MNPQ is similar to Trapezoid RSTU. What is the length of the "x" on the misside side NP ? Also, what is the length of
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Answer:

x =  15

y =  25

Step-by-step explanation:

Given

See attachment for MNPQ and RSTU

Required

Find x and y

To solve this question, we make use of equivalent ratios of corresponding side lengths.

The ratio of corresponding sides are:

MN : RS

NP : ST

PQ : TU

MQ : RU

From the attachment, we have:

MN : RS \to 18 : 30

NP : ST \to x : 25

PQ : TU \to 15 : y

To solve for x, we equate MN : RS and NP : ST

18 : 30 = x : 25

Express as fraction

\frac{18 }{ 30 }= \frac{x }{ 25}

Make x the subject

x =  25 * \frac{18 }{ 30 }

x =  \frac{25 * 18 }{ 30 }

x =  \frac{450}{ 30 }

x =  15

To solve for y, we equate MN : RS and PQ : TU

18 : 30 = 15 : y

Express as fraction

\frac{18 }{ 30 }= \frac{15 }{ y}

Make y the subject

y = 15 * \frac{30 }{ 18 }

y =  \frac{15 *30}{ 18 }

y =  \frac{450}{ 18 }

y =  25

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Answer: 1 one

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