=4(4x+2y+x-y)
=4*4x+4*2y+4*x-4*y
=16x+8y+4x-4y
=16x+4x+8y-4y
=20x+4y
donc la bonne reponse est la 3
4(5x+y)*
=4*5x+4*y
=20x+4y
SIDE LENGTH OF TRIANGLE: 2.14 inches
SIDE LENGTH OF HEXAGON: 6 inches
To solve this problem, we know that the shapes have equal sides as it states “equilateral triangle”. A triangle has 3 sides and a hexagon has 6 sides. We are told the perimeters are the same so you can set their perimeters equal to each other to solve for x. You would get this : 3(1.4x + 2) = 6(0.5x +2)
With basic algebra you would get x= 5
Then you substitute that value into the length sides of the triangle and hexagon. For the triangle you would approx get 2.14 inches and for the hexagon 6 inches
Answer:
d
By the alternate interior angles theorem,
- Angles ABD and BAC will be congruent
- Angles BAD and ABC will be congruent
By the reflexive property, AB is congruent to itself.
Thus, the triangles will be congruent by ASA.
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Answer:
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Step-by-step explanation:
let's solve :-
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