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Ainat [17]
3 years ago
12

36 irrational or rational and why?

Mathematics
2 answers:
Degger [83]3 years ago
5 0

Answer:

Rational

Step-by-step explanation:

First tip with numbers... All whole numbers are rational and all numbers, rational or irrational are real numbers. Rational numbers consist of whole numbers, integers, fractions, and so on... While irrational numbers are numbers that can't be simplified to a basic whole number or fraction like 36.

Pi (π) is an example of an irrational number.

36 is an example of a rational number.

Hope you get it now! :)

bazaltina [42]3 years ago
4 0
Rational number because for a number to be irrational it needs to have a decimal or be smaller than 1
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y=kx

<h2>Explanation:</h2>

When we say that an amount of something increases as another amount increases, at the same rate, then we are talking about Direct Proportion. It is also true for an amount of something that decreases as another amount decreases, at the same rate. So "y varies directly as x" can be written as:

y\propto x

In other words:

y=kx

Where k is the constant of proportionality, and represents the slope of a line that passes through the origin.

<h2>Learn more:</h2>

About this subject: brainly.com/question/12809482

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<u><em>Answer:</em></u>
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<u><em>Explanation:</em></u>
The graph of the given function is shown in the attached image.

<u><em>Let's check the options given:</em></u>
<u>Option 1:</u>
<span>As x approaches positive infinity, f(x) approaches negative infinity.
This option is incorrect as we can note that as the value of x increases approaching positive infinity, the value of f (x) also increases approaching positive infinity

<u>Option 2:</u>
</span><span>As x approaches negative infinity. f(x) approaches negative infinity.
</span>This option is correct as we can note that as the value of x decreases approaching negative infinity, the value of f (x) also decreases approaching negative infinity

<u>Option 3:</u>
<span>As x approaches negative infinity, f(x) approaches positive infinity.
</span>This option is incorrect as we can note that as the value of x decreases approaching negative infinity, the value of f (x) also decreases approaching negative infinity

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Hope this helps :)

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