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Wittaler [7]
3 years ago
10

Need help with angle measurements

Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0

Answer: How about u try this

75 + 53 = 128

180 - 128 = 52

75 + 53 + 52 = 180

missing angle is 52

if they are both in and out they are both the same 52

So Angle 1 is 52

I dont know if this helps but i tried tho

Step-by-step explanation: Good night!

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You wish to estimate a population proportion with a confidence interval with a margin of error no larger than 0.03. You have a b
NikAS [45]

Answer:

The answer is 0.8788

Step-by-step explanation:

<em>From question given, let us recall the following:</em>

<em>We know that  Ƶα /2  * √p (1-p)/n</em>

<em>when we use  n≤  5000/10 =500</em>

<em> P = 0.75</em>

<em>The Margin of error = 0.03</em>

<em>Putting this values together we arrive at </em>

<em> Ƶα/2 = 0.03/√0.75 * 0.25/500 </em>

<em>= 1.549</em>

<em>Now,</em>

<em>Ф (1.549) = 0.9394</em>

<em>Therefore the confidence level becomes:</em>

<em> 1- (1-∝)/2 = 0.9394</em>

<em>∝ = 0.8788</em>

<em>The answer is 0.8788</em>

<em />

8 0
4 years ago
Which are examples of non-statistical questions?
4vir4ik [10]
I think it’s questions 1 and 2
6 0
3 years ago
How do you prove theorems behind two parallel lines cut by a transversal?
LenaWriter [7]
The way to do it can be explained like this:
Say AB and CD are the two parallel lines cut by a transversal at E and F respectively.
 Then the pairs of alternate interior angles are:
Angle(AEF) and Angle(DFE)
Angle(CFE) and Angle(BEF)
Now lets prove if this is true:
<span>Angle(CFE) +Angle(DFE) = 180
(linear pair)
Also
Angle(CFE) +Angle(AEF) = 180
(Corresponding angles)
</span><span>Equate the above results:
Angle(CFE) +Angle(DFE) = Angle(CFE) +Angle(AEF)
</span><span>Angle(DFE) = Angle(AEF)
</span>Happens the same with
<span>Angle(CFE) = Angle(BEF)
</span>Hope this is very useful for you

5 0
3 years ago
I really need help!!!!
vivado [14]
In this situation, choose length and width such that 12.75=l*w. writing it as a mixed number you have 51/4=sqrt51/2*sqrt51/2 or any other combination you can use.
8 0
3 years ago
Braydon is at the 10-mile Marker at the park to run. He can run at a pace of 3 miles per hour. Lauren is at the 12-mile marker a
madreJ [45]

it will take 1.33 hours for Braydon and Lauren to  get to the same mile marker on the path in the  park .

<u>Step-by-step explanation:</u>

Here we have , Braydon can run at 3 miles per hour , he's initially at 10 mile marker . Lauren is at the 12-mile marker at the park, She is walking at a pace of 1.5 miles per hour. We need to find How long will it take for Braydon and Lauren to  get to the same mile marker on the path in the  park .Let's find out:

Let after time t they meet each other so ,  Braydon can run at 3 miles per hour , he's initially at 10 mile marker . Distance traveled is given by :

⇒ 3t+10

Now , Lauren is at the 12-mile marker at the park, She is walking at a pace of 1.5 miles per hour , Distance traveled is given by :

⇒ 1.5t + 12

Equating both we get :

⇒ 3t+10=1.5t+12

⇒ 1.5t=2

⇒ t=\frac{2}{1.5}

⇒ t=1.33

Therefore , it will take 1.33 hours for Braydon and Lauren to  get to the same mile marker on the path in the  park .

7 0
3 years ago
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