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Wittaler [7]
3 years ago
10

Need help with angle measurements

Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0

Answer: How about u try this

75 + 53 = 128

180 - 128 = 52

75 + 53 + 52 = 180

missing angle is 52

if they are both in and out they are both the same 52

So Angle 1 is 52

I dont know if this helps but i tried tho

Step-by-step explanation: Good night!

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Question 12
katovenus [111]

s = 50d + 25

55 = 50d + 25

55 - 25 = 50d + 25 - 25

30 = 50d

\frac{30}{50} =  \frac{50d}{50}

0.6 = d

Your car would slide a distance of 0.6 feet.

3 0
3 years ago
I need the Point-Slope Form Equation
kondaur [170]

Point-Slope Equation: y - y₁ = m(x - x₁) ; where (x₁, y₁) is the point and m is the slope

(x₁, y₁) = (4, 1700)   and   m = 200

y - 1700 = 200(x - 4)

Answer: bottom left

5 0
4 years ago
Can some one please help!!!
LenKa [72]
120×2 maybe? hope I helped
5 0
3 years ago
Two forces act on an object. The first Force has a magnitude of 300 Newtons and acts at an angle of 30 degrees as measured from
alina1380 [7]
This is a question of resolving the forces in question into horizontal and vertical and then finding the action of the resultant force.
The first force acts at an angle less than 90° and thus its resolved forces are positive. The second force acts at angle larger than 90° and is incident and thus its horizontal value is positive while its vertical value is negative.

Therefore;
For force of 300 N at 30°;
Horizontal value = 300*Cos 30 = 259.81 N
Vertical value = 300*Sin 30 = 150 N

For 150 N at 135°;
Horizontal value = 150*Cos (180-135) = 106.07 N
Vertical value = -150*Sin (180-135) = -106.07 N

Then,
Resultant horizontal value = 259.81+106.07 = 365.88 N
Resultant vertical value = 150-106.07 = 43.93 N

Therefore,
Resultant force, v = Sqrt (365.88^2+43.93^2) = 368.51 N
Angle of action measured from horizontal = tan ^-1(43.93/365.88) 6.85°

Then,
v = 368.51 N at 6.85° from horizontal
5 0
4 years ago
Solve for x in the equation x2 + 14x+17--96
Veseljchak [2.6K]

Answer:

Option B.

Step-by-step explanation:

If a quadratic equation is defined as ax^2+bx+c=0, the by quadratic formula

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Consider the given equation is

x^2+14x+17=-96

We need to find the value of x.

Add 96 on both sides.

x^2+14x+17+96=-96+96

x^2+14x+113=0

Here, a=1, b=14 and c=113. Using quadratic formula we get

x=\dfrac{-14\pm \sqrt{14^2-4(1)(113)}}{2(1)}

x=\dfrac{-14\pm \sqrt{-256}}{2(1)}

x=\dfrac{-14\pm \sqrt{256}\sqrt{-1}}{2}           (\sqrt{-1}=i)

x=\dfrac{-14\pm 16i}{2}

x=-7\pm 8i

The value of x are x=-7 + 8i and x=-7 - 8i.

Therefore, the correct option is B.

8 0
3 years ago
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