-3x^2+2xy-y^3 for x = 5 and y = -1
2 answers:
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so the triangle has the vertices of (2, 18) (-2, -4), and (6,12), that gives us the endpoints for each line of
(2, 18) , (-2, -4)
(-2, -4) , (6,12)
(6,12) , (2, 18)
so the triangle has the vertices of (2, 18) (-2, -4), and (6,12), that gives us the endpoints for each line of
(2, 18) , (-2, -4)
(-2, -4) , (6,12)
(6,12) , (2, 18)