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Sav [38]
4 years ago
8

A cell phone provider offers a plan that costs ​$40 per month plus ​$0.20 per text message sent or received. A comparable plan c

osts ​$50 per month but offers unlimited text messaging. Complete parts a. and b. below. a. How many text messages would have to be sent or received in order for the plans to cost the same each​ month? In order for the plans to cost the​ same,____ text messages would have to be sent or received.
Mathematics
1 answer:
Svetradugi [14.3K]4 years ago
4 0
You do the following.

Take the price of the most expensive subscription and retract the price of the cheap one.

$50-$40 = $10

Since we know what the price of a text message and the difference in dollars between the two subscriptions, we can calculate how many text messages has to be sent. We just divide the result from before ($10) with the price of a text message ($0.2)

$10/$0.2 = 50

The total number of text messages that needs to be send in order for the price of the subscriptions to be the same, is 50.
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Answer:

Step-by-step explanation:

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\Delta_1=\left| \begin{array}{ccc}13&1&2\\8&1&-2\\11&2&1\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\8&1&-2\\\frac{11}{2}& 1&\frac{1}{2}\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\-5&0&-4\\\frac{-5}{2}& 0&\frac{5}{2}\end{array}\right| \\\\=2*(-1)*(\frac{-25}{2}-\frac{20}{2}) =45\\

\Delta_2=\left| \begin{array}{ccc}2&13&2\\1&8&-2\\1&11&1\end{array}\right| \\\\\\=\left| \begin{array}{ccc}3&21&0\\3&30&0\\1&11&1\end{array}\right| \\\\\\=1*(90-63) =27\\

\Delta_3=\left| \begin{array}{ccc}2&1&13\\1&1&8\\1&2&11\end{array}\right| \\\\\\=\left| \begin{array}{ccc}0&-1&-3\\0&-1&-3\\1&2&11\end{array}\right| \\\\\\=0\\

\left\{\begin{array}{ccc}x=\dfrac{\Delta_1}{\Delta}=\dfrac{45}{9}=5\\\\y=\dfrac{\Delta_2}{\Delta}=\dfrac{27}{9}=3\\\\z=\dfrac{\Delta_3}{\Delta}=\dfrac{0}{9}=0\\\end{array}\right.

8 0
3 years ago
Find the horizontal or oblique asymptote of f(x) = negative 2 x squared plus 3 x plus 6, all over x plus 1.
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For the answer to the question above I' ll provide the solutions below.
        2x + 3 
<span>        ------------------- </span>
<span>x+1 | 2x^2 + 5x + 6 </span>
<span>        2x^2 + 2x </span>
<span>        ------------- </span>
<span>                    3x + 6 </span>
<span>                    3x + 3 </span>
<span>                   -------- </span>
<span>                            3 </span>
So the answer on <span>the oblique asymptote is y = 2x + 3.
</span>I hope my answer helped you. Have a nice day!
5 0
3 years ago
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B) A man purchased 5 dozen of eggs at Rs 5 each. 10 eggs were broken and he
aev [14]

Answer:

Dear User,

Answer to your query is provided below

(i) Total Loss = Rs.15

(ii) Loss percent = 5%

Step-by-step explanation:

Eggs purchased = 5x12 = 60

Total Cost = 60x5 = Rs 300

Eggs Broken = 10

Eggs Broken cost = 10x5= Rs. 50

Eggs sold = 60-10 = 50

Egg Sale cost = 50x5.70 = Rs 285

(i) Total Loss = C.p. - S.p. = 300 - 285 = 15

(ii) Loss Percent = (Loss/CP)x100 = (15/300)x100 = 5%

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4 years ago
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Answer:

c. X= {0,1,3}

Step-by-step explanation:

We have these possible outcomes:

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One assigned to their favorite city(The other two are assigned to the other's favorite city).

All are assigned to their favorite city.

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If two peooke are assigned to their favorite city, the third person necessary has to be assigned to their favorite city, as it will be the only option remaining.

So the correct answer is given by option c.

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