Question

Need help with problems 16 and 17, please? I'll do brainiac

Answer 1

Answer: 16) y=-0.5x+3 and 17) y=2x-3

Step-by-step explanation:

16: The slope-intercept form of a line is y=mx+b, where m is the slope, and b is the y-value at the y-intercept.

Since y=3 at x=0, the y-intercept is (0,3), and b=3.

Slope=$\frac{y_{2} -y_{1} }{x_{2}-x_{1} }$ where ($x_{1} ,y_{1}$) and ($x_{2} ,y_{2}$) are two points on the line. Choose (0,3) and (2,2):

Slope=$\frac{2-3}{2-0}$=-0.5

Plug m=-0.5 and b=3 into y=mx+b:

y=-0.5x+3

17: The slope-intercept form of a line is y=mx+b, where m is the slope, and b is the y-value at the y-intercept.

Because y=-3 at x=0, the y-intercept is (0,-3), and b=-3.

Slope=$\frac{y_{2} -y_{1} }{x_{2}-x_{1} }$ where ($x_{1} ,y_{1}$) and ($x_{2} ,y_{2}$) are two points on the line. Choose (0,-3) and (1,-1):

Slope=$\frac{-3-(-1)}{0-1}$=$\frac{-2}{-1}$=2

Plug m=2 and b=-3 into y=mx+b:

y=2x-3