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BARSIC [14]
3 years ago
5

Solve: x^2+7x-30=0 Please show all the steps, thank u

Mathematics
1 answer:
vodomira [7]3 years ago
8 0

x^2+7x-30=0 Rewrite the expression.

x^2+10x-3x-30=0 Factor the expressions.

x(x+10)-3 (x+10)=0 Factor the expression.

(x+10)(x-3)=0 Separate into possible cases.

x+10=0

Solve.

x-3=0

x1= -10

x2= 3

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Why is it important to know how to estimate quotients?
Zigmanuir [339]
In the real world you are not going to have a calculator on you 24/7. Nor will you have a pencil or paper to do longhand. You need to know how to accurately estimate your answers in order to be successful.
8 0
3 years ago
-6(a + 8)<br> I need help!
Yuliya22 [10]

Answer: I got -6a + 48

Step-by-step explanation:I distributed and I got negative 6a because when you distributed the variable goes with whatever number is before it and I got 48 because -6 multiplied by 8 you get positive 48 because the 8 is bigger then the negative 6 so I don't know if your teacher wants you to solve for the answer but like I said I got -6a + 48

8 0
3 years ago
An airline finds that 5% of the persons making reservations on a certain flight will not show up for the flight. If the airline
vivado [14]

Answer:

The answer to the question is;

The probability that a seat will be available for every person holding a reservation and planning to fly is 0.63307.

Step-by-step explanation:

Let the sample size =n = 100

The success probability = 5 % = 0.05

Number of tickets sold = 105 tickets

In the case where there the airline has found that 5 % will not show up, then every passenger should have  a seat, we have  

A Binomial distribution is appropriate where there is a chance for a certain number of successful outcomes from a number of independent trails

However n·p and n·q must be ≥ 5 for there to be a normal approximation of a Binomial distribution thus

n·p = 105×0.05 =  5.25 ≥ 5

and n·q = n(1 - p) = 105 (1 - 0.05) = 99.75 ≥ 5

As the requirements are met, we can proceed with the approximation of the Binomial distribution by the normal distribution

 z = \frac{x-np}{\sqrt{np(1-p)}  } = \frac{4.5 - 105*0.05}{\sqrt{105*0.05(1-0.05)} } =  - 0.3358

We therefore have P(x ≥ 5) = P( x > 4.5) = P(z > -0.34) = 1 - P(z < -0.34) = 1 -0.36693 = 0.63307

Another way to solve the question is as follows

p = 0.95 q = 0.05

μ = np = 0.95*105 = 99.75, σ = \sqrt{npq} = 2.233

P (x≤100) = P(z = P(z<0.34) = 0.63307.

6 0
3 years ago
What is BC ? Enter your answer in the box.
omeli [17]

Answer:

Before Christ

Step-by-step explanation:

This is a historical term which is the opposite of AD(Anno Domini)

I do not know if I have spelt Anno Domini correctly but it does not matter


4 0
3 years ago
~[~p/\(q\/~p)] true or false
iren [92.7K]
I believe you're answer is false.
6 0
3 years ago
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