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3 years ago

I need help with this problem please

Mathematics

2 answers:

Dennis_Churaev [7]3 years ago

7 0

Answer:

j = 2/3

Step-by-step explanation:

-2/3 = -j

j = 2/3

GrogVix [38]3 years ago

3 0

Answer:

j = 2/3

Step-by-step explanation:

-1/3 = -1/2 j

Multiply each side by -2

-1/3 * -2 = -1/2 j * -2

2/3 =j

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“encontrar la integral indefinida y verificar el resultado mediante derivación”

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Haz la sustitución:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

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Para confirmar el resultado:

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Sustituye:

$y=1+x^3\implies\mathrm dy=3x^2\,\mathrm dx$

$\implies I=\displaystyle\frac13\int\frac{\mathrm dy}{y^2}=-\frac1{3y}+C=-\frac1{3(1+x^3)}+C$

(Te dejaré confirmar por ti mismo.)

$I=\displaystyle\int\frac x{\sqrt{1-x^2}}\,\mathrm dx$

Sustituye:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{\sqrt y}=-\frac12(2\sqrt y)+C=-\sqrt{1-x^2}+C$

$I=\displaystyle\int\left(1+\frac1t\right)^3\frac{\mathrm dt}{t^2}$

Sustituye:

$u=1+\dfrac1t\implies\mathrm du=-\dfrac{\mathrm dt}{t^2}$

$\implies I=-\displaystyle\int u^3\,\mathrm du=-\frac{u^4}4+C=-\frac{\left(1+\frac1t\right)^4}4+C$

Podemos hacer que esto se vea un poco mejor:

$\left(1+\dfrac1t\right)^4=\left(\dfrac{t+1}t\right)^4=\dfrac{(t+1)^4}{t^4}$

$\implies I=-\dfrac{(t+1)^4}{4t^4}+C$

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