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Anuta_ua [19.1K]
3 years ago
7

1) Classify the following attributes as binary, discrete, or continuous. Also classify them as qualitative (nominal or ordinal)

or quantitative (interval or ratio). Some cases may have more than one interpretation, so briefly indicate your reasoning if you think there may be some ambiguity.
Example: Age in years.
Answer: Discrete, quantitative, ratio
a) Time in terms of AM or PM.
b) Brightness as measured by a light meter.
c) Brightness as measured by people's judgments.
d) Angles as measured in degrees between 0 and 360.
e) Bronze, Silver, and Gold medals as awarded at the Olympics.
f) Height above sea level.
Mathematics
1 answer:
Viktor [21]3 years ago
6 0

Answer:

a) Time in terms of AM or PM: Binary, qualitative and nominal (binary attributes are considered nominal)

b) Brightness as measured by a light meter: Ratio, quantitative and continuous.

c) Brightness as measured by people's judgments: Discrete, qualitative and ordinal (assuming they're chosen discretely)

d) Angles as measured in degrees between 0 and 360: Ratio, quantitative and continuous.

e) Bronze, Silver, and Gold medals as awarded at the Olympics: Qualitative, discrete and ordinal.

f) Height above sea level: Quantitative, continuous, ratio/interval (depending if it's seen as an arbitrary origin).

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Step-by-step explanation:

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4

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7/1, I think that’s right
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In basketball, baskets are worth either 2 or 3 points. A missed shot, of course, is worth 0 points. During the 2007-2208 season,
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1.15

Step-by-step explanation:

Multiply each shot by its point value. Then add. Divide this sum by the total number of shots taken.

288*2 + 79*3 + 340*0 = 813

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7 0
2 years ago
What is the easiest way to solve a quadratic equation?​
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Answer: This is an opinion, look below! :)

Step-by-step explanation:

Factor the expression. To factor the expression, you have to use the factors of the {\displaystyle x^{2}}x^{2} term (3), and the factors of the constant term (-4), to make them multiply and then add up to the middle term, (-11). Here's how you do it:

Since {\displaystyle 3x^{2}}3x^{2} only has one set of possible factors, {\displaystyle 3x}3x and {\displaystyle x}x, you can write those in the parenthesis: {\displaystyle (3x\pm ?)(x\pm ?)=0}(3x\pm ?)(x\pm ?)=0.

Then, use process of elimination to plug in the factors of 4 to find a combination that produces -11x when multiplied. You can either use a combination of 4 and 1, or 2 and 2, since both of those numbers multiply to get 4. Just remember that one of the terms should be negative, since the term is -4.[3]

By trial and error, try out this combination of factors {\displaystyle (3x+1)(x-4)}(3x+1)(x-4). When you multiply them out, you get {\displaystyle 3x^{2}-12x+x-4}3x^{2}-12x+x-4. If you combine the terms {\displaystyle -12x}-12x and {\displaystyle x}x, you get {\displaystyle -11x}-11x, which is the middle term you were aiming for. You have just factored the quadratic equation.

As an example of trial and error, let's try checking a factoring combination for {\displaystyle 3x^{2}-11x-4=0}3x^{2}-11x-4=0 that is an error (does not work): {\displaystyle (3x-2)(x+2)}(3x-2)(x+2) = {\displaystyle 3x^{2}+6x-2x-4}3x^{2}+6x-2x-4. If you combine those terms, you get {\displaystyle 3x^{2}-4x-4}3x^{2}-4x-4. Though the factors -2 and 2 do multiply to make -4, the middle term does not work, because you needed to get {\displaystyle -11x}-11x, not {\displaystyle -4x}-4x.

7 0
3 years ago
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