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SCORPION-xisa [38]
3 years ago
11

PLEASE HELP MATH 10+ POINTS PLEASE

Mathematics
2 answers:
DENIUS [597]3 years ago
6 0

Answer:

80

Step-by-step explanation:

tankabanditka [31]3 years ago
3 0

Answer:

749

Step-by-step explanation:

8349

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3in

Step-by-step explanation:

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3 years ago
Solve irrational equation pls
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\hbox{Domain:}\\&#10;x^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\\&#10;x^2-x+2x-2\geq0 \wedge x^2-x-3x+3\geq0 \wedge x^2\geq1\\&#10;x(x-1)+2(x-1)\geq 0 \wedge x(x-1)-3(x-1)\geq0 \wedge (x\geq 1 \vee x\leq-1)\\&#10;(x+2)(x-1)\geq0 \wedge (x-3)(x-1)\geq0\wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\&#10;x\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\&#10;x\in(-\infty,-2\rangle\cup\langle3,\infty)


&#10;\sqrt{x^2+x-2}+\sqrt{x^2-4x+3}=\sqrt{x^2-1}\\&#10;x^2-1=x^2+x-2+2\sqrt{(x^2+x-2)(x^2-4x+3)}+x^2-4x+3\\&#10;2\sqrt{(x^2+x-2)(x^2-4x+3)}=-x^2+3x-2\\&#10;\sqrt{(x^2+x-2)(x^2-4x+3)}=\dfrac{-x^2+3x-2}{2}\\&#10;(x^2+x-2)(x^2-4x+3)=\left(\dfrac{-x^2+3x-2}{2}\right)^2\\&#10;(x+2)(x-1)(x-3)(x-1)=\left(\dfrac{-x^2+x+2x-2}{2}\right)^2\\&#10;(x+2)(x-3)(x-1)^2=\left(\dfrac{-x(x-1)+2(x-1)}{2}\right)^2\\&#10;(x+2)(x-3)(x-1)^2=\left(\dfrac{-(x-2)(x-1)}{2}\right)^2\\&#10;(x+2)(x-3)(x-1)^2=\dfrac{(x-2)^2(x-1)^2}{4}\\&#10;4(x+2)(x-3)(x-1)^2=(x-2)^2(x-1)^2\\
&#10;4(x+2)(x-3)(x-1)^2-(x-2)^2(x-1)^2=0\\&#10;(x-1)^2(4(x+2)(x-3)-(x-2)^2)=0\\&#10;(x-1)^2(4(x^2-3x+2x-6)-(x^2-4x+4))=0\\&#10;(x-1)^2(4x^2-4x-24-x^2+4x-4)=0\\&#10;(x-1)^2(3x^2-28)=0\\&#10;x-1=0 \vee 3x^2-28=0\\&#10;x=1 \vee 3x^2=28\\&#10;x=1 \vee x^2=\dfrac{28}{3}\\&#10;x=1 \vee x=\sqrt{\dfrac{28}{3}} \vee x=-\sqrt{\dfrac{28}{3}}\\

There's one more condition I forgot about
-(x-2)(x-1)\geq0\\&#10;x\in\langle1,2\rangle\\

Finally
x\in(-\infty,-2\rangle\cup\langle3,\infty) \wedge x\in\langle1,2\rangle \wedge x=\{1,\sqrt{\dfrac{28}{3}}, -\sqrt{\dfrac{28}{3}}\}\\&#10;\boxed{\boxed{x=1}}
3 0
3 years ago
1.The entry tickets at a community fair cost $5 for children and $10 for adults. On a certain day 1000 people entered in the fai
ZanzabumX [31]

Answer:

568 ADULTS

284 CHILDREN

Step-by-step explanation:

5C+10A=7100

A=2C

5C +10(2C)=7100

5C+20C=7100

25C=7100

C=284

A=2C

A=568

BRAINLIEST???

8 0
3 years ago
Sharon is planning a holiday for 4 people for 7 days.
Eduardwww [97]
1 person = 130 + (60x7) + 350 = 900
4 people = 4 x 900 = 3600
I think this is right !
6 0
3 years ago
Read 2 more answers
At 7:30 a.m., a bus left Town P for Town Q at a speed of 60 kilometers per hour. 15 minutes later, a car left Town Q and headed
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Answer:

the bus took 4.5 hrs going 60 kph to get from town P to town Q

this means that the distance from town P to town Q is 270 km

side note-the car kph isn't shown and it got to town Q faster than the bus, so it must have gone at a faster speed. i didn't use the car to solve the problem, just the bus.

5 0
3 years ago
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