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Lynna [10]
2 years ago
13

Find the area of the shaded region A. 4.421 B. 3.982 C.4.215 D. 3.769

Mathematics
1 answer:
jasenka [17]2 years ago
3 0

Answer:

b i think

Step-by-step explanation:

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0.0090 in scientific notation
netineya [11]

Answer: 9 x 10^{-3}

Step-by-step explanation:

4 0
3 years ago
Can someone please help me
ruslelena [56]

Answer:

e

Step-by-step explanation:

4 0
3 years ago
A Japanese bullet train travels 558 miles per 3 hours A. What is the rate B. How far does the train travel in 1 hour WHO EVER A
Delicious77 [7]

Answer:

Step-by-step explanation:

Remark

The rate is going to be the same as the distance travelled in 1 hour. The units will be different.

Formula

d = r * t

Givens

d = 558 miles

t = 3 hours

Problem A

r = d / t

r = 558/ 3 = 186 miles / hr

Problem B

Givens

r = 186 miles / hour

t = 1 hour

d = ?

Solution

d = 186 mi/hr * 1 hr

d = 186 miles

<u>Note</u>

This looks really trivial, but it's not. You have to learn to see the difference between a number and its units. It's not very often that the numbers will be the same, but if the units differ, then it is an entirely different question.

7 0
2 years ago
In a circle, what is the ratio of the circumference to its diameter?
NemiM [27]

Answer:

D. pi

Step-by-step explanation:

Circumference of a circle = \pi d

Diameter = d

Therefore, ratio of circumference of a circle to its diameter would be:

\pi d : d

= \frac{\pi d}{d} = \pi => (d cancels d)

Therefore, the ratio of the circumference of a circle to its diameter is \pi

4 0
3 years ago
Given sinθ=- 3/5 and cscθ=-5/3 in quadrant III, find the value of other trigonometric functions using a Pythagorean Identity. Sh
Yakvenalex [24]
Let ABC be a triangle in the 3rd quadrant, right-angled at B. 
 So, AB-> Perpendicular BC -> Base AC -> Hypotenuse. 
Given: sinθ=-3/5 cosecθ=-5/3 
 According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
 Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
 Since sinθ=Perpendicular/Hypotenuse ,
 AC=5 and AB=3
 Substituting these values in equation (1)
 
〖BC〗^2=〖AC〗^2-〖AB〗^2

 ă€–BC〗^2=5^2-3^2
 

 ă€–BC〗^2=25-9

 ă€–BC〗^2=16

 BC=4 units

 Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
 So,cosθ=Base/Hypotenuse Cosθ=-4/5 
 secθ=Hypotnuse/Base secθ=-5/4 
 tanθ=Perpendicular/Base tanθ=3/4  
 cotθ=Base/Perpendicular cotθ=4/3
4 0
2 years ago
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