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monitta
3 years ago
15

The concentration of the substance outside the cell and C2 represents the concentration of the substance

Mathematics
1 answer:
BigorU [14]3 years ago
6 0

Is this math? I'm sorry I don't get what formula I'm supposed to rewrite or -

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Please help if you can Thank you so much!
Vladimir [108]

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I just relearned this yesterday

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Plot the points A(9, 11) and B(–3, –5). Find midpoint M of AB. Then show that AM = MB and AM + MB =AB
Alex_Xolod [135]

Answer:

The midpoint is (3, 3).

Step-by-step explanation:

We are given the two points A(9, 11) and B(-3, -5).

The midpoint is given by:

\displaystyle M=\Big(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\Big)

So:

\displaystyle M =  \Big( \frac{9+(-3) }{2}, \frac{ 11+(-5) }{2} \Big) = (3,3)

The midpoint is (3, 3).

We want to show that AM = MB.

We can use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

The distance between A(9, 11) and M(3, 3) will then be:

AM=\sqrt{(9-3)^2+(11-3)^2}=\sqrt{6^2+8^2}=\sqrt{100}=10

And the distance between B(-3, -5) and M(3, 3) will be:

MB = \sqrt{ (3-(-3))^2 + (3-(-5))^2 } = \sqrt{(6)^2+(8)^2} = \sqrt{ 100 } = 10

So, AM = MB = 10.

Since AM = MB = 10, AM + MB = 10 + 10 = 20.

So, we want to prove that AB = 20.

By the distance formula:

AB=\sqrt{(9-(-3))^2+(11-(-5))^2}=\sqrt{12^2+16^2}}=\sqrt{400}=20\stackrel{\checkmark}{=}20

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3 years ago
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Which graphic organizer is most helpful when comparing and contrasting information?
Musya8 [376]
A. a Venn diagram. A Venn diagram is two circles that overlap in the middle. Each circle represents a different subject. The overlapping part is used for comparing, while the rest of the circles are used for contrasting.
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