52/8 is 6.5 which is 6.5 days 15-6.5 is 8.5 and 8.5 • 8 is 68. 68+52 is the same as 15•8 so i’m pretty sure the answer is 68
Answer:
18,176
Step-by-step explanation:
Figure out an easier thing to do: 1000 - 2021 = 9,797.
Therefore, our answer will be like 9999999999999999999999997979. Out of all of these digits, there are only 2 that arent nines. We know the amount of digits since it's 10^2021 power. We will have one less since we are subtracting 2021. Therefore, 2020 digits in total. Now we know of those 2020 digits, 2 of them are 7, therefore 2018 of them are 9s. That means do 2018(9) + 2(7) = 14 + 18,162 = 18,176.
Answer:
The arcs are drawn to find a point on the bisecting ray. If the arcs are the same width, it makes sure that they are equidistant from the points on the rays of the angle. This causes the point to be on the bisecting ray.
Step-by-step explanation:
Bisection of an angle implies dividing the angle into two equal parts. The ray that divides the angle is called a bisector.
The hunter should use the same radius or width to draw the two arcs, using points P and Q as the center interchangeably, so that they would intersect at an equidistant point to P and Q. The point of intersection lies on the bisecting ray of the angle.
The value of D should be 4
The unit rate is 60 miles per hour and the driver will reach before time with the calculated constant speed
Step-by-step explanation:
Given
Distance = d = 45 miles
Time = t = 3/4 hour
The unit rate is defined as the distance per unit time. In this case, the unit rate can also be called speed.
So,
Using this unit rate we can see if the car can travel 65 miles in 1.25 hours or not
Given
Distance = d1 = 65 miles
Speed = s = 60 miles per hour
Putting the values in the formula for speed
As we can see that 1.08 is less than 1.25 so the driver will reach the meeting before time if he drives on a constant speed of 60 miles per hour
Hence,
The unit rate is 60 miles per hour and the driver will reach before time with the calculated constant speed
Keywords: Speed, unit rate
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