First multiply 3 and the 1
Then simplify b^2-4b+3=0
Then divide both numbers by 3 (b-3/3)(b-1/3)=0
If it doesn’t go in even like the second term then bring it before the B
Then equal both terms to 0 and solve
Since two people take both courses, we can subtract two from 7, 8, and 21, giving us 5, 6, and 19.
Add 5 and 6 together to get 11. Since eleven students are in those two groups, we can answer this. The answer will be 11/19.
137,638
+52,091
-------
189,729 ⇨ 189,730
Option D.
H = 90 + 2.50r (Henry makes a flat rate of 90 and 2.50 per repair.)
Y = 75 + 5.25s (Yolanda makes a flat rate of 75 and 5.25 per sale.)