How do I know that 15/30 is greater than 1/3 but less than2/3
2 answers:
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The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
What is the intermediate value theorem?
Intermediate value theorem is theorem about all possible y-value in between two known y-value.
x-intercepts
-x^2 + x + 2 = 0
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1, x = 2
y intercepts
f(0) = -x^2 + x + 2
f(0) = -0^2 + 0 + 2
f(0) = 2
(Graph attached)
From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3
For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.
<em>Your question is not complete, but most probably your full questions was</em>
<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>
Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
Learn more about intermediate value theorem here:
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Answer:
The standard form of a quadratic is y = ax^2 + bx + c.
- In this equation, the formula for the axis of symmetry is x =
.
- You know that the center will always be along that line, and you've got the x-coordinate already, so just plug that in and get the y-coordinate out for the center.
The vertex form of a quadratic is also helpful, y = a(x-h)^2 + k.
- In this equation, the formula for the center is (h, k), and the axis of symmetry is x = h! That's even easier!