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3 years ago

(a + b - c)(a + b + c)

Mathematics

2 answers:

lions [1.4K]3 years ago

4 0

Answer:3

Step-by-step explanation:

Anna007 [38]3 years ago

4 0

A^2+2ab+b^2-c^2 hopefully I helped

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Kona’s mother realized that her age is the difference of Kona’s age squared and four. If k represents Kona’s age, which expressi

solmaris [256]

Answer:

k squared minus 4/ A

Step-by-step explanation:

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2 years ago

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"Find x" I managed to get -6/2c, I just want to double check if that is correct

Soloha48 [4]

- 6/2c is the correct solution

collect like terms : 3cx - cx = 2cx

hence 2cx = - 6

dividing both sides by 2c gives x = - 6/2c

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3 years ago

Unit 3 Test ( Similarity ) Find GK

fredd [130]

Answer:

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Step-by-step explanation:

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2 years ago

Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

Nonamiya [84]

Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

6 0

3 years ago

Read 2 more answers

Please solve this the question is in the picture

Dominik [7]

Answer:

x : -3

Step-by-step explanation:

1) 15x-3(3x + 4) = 6 (distribute -3 to the numbers on the inside of parentheses)

2) 15x - 9x - 12 =6 (combine like terms 15x-9x = 6x)

3) -6x - 12 = 6 (add twelve to both sides, add the 12 to cancel out the 12)

4) -6x = 18 (divide the -6 on both sides)

5) x = -3

7 0

3 years ago

(a + b - c)(a + b + c)​

(a + b - c)(a + b + c)