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Inessa05 [86]
3 years ago
11

Which number line shows the inequality 4x-3>-7

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
5 0

x>-1

Step-by-step explanation:

I don't see any number lines but it would be one with an open circle going right from -1.

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Which expression is equivalent to –6x3 • x • y2 • y6?
Olenka [21]
<span>–6x^3 • x • y^2 • y^6
= - 6x^4y^8

answer
</span>- 6x^4y^8

hope it helps
4 0
3 years ago
Read 2 more answers
F(x) = (3.x4 + 1)2<br> Determine the total number of roots of each polynomial function
Black_prince [1.1K]

Answer:

6

Step-by-step explanation:

4 0
3 years ago
Find 10-3. write the subtraction fact two ways.
vesna_86 [32]
10-3=7 3-10=7 if u need help with anything else u can ask
6 0
3 years ago
The slope of a line that is parallel to each line whose equation is given
Kobotan [32]
Parallel lines, slope is the same so
1) 3x+8y = 12
8y = -3x + 12
  y = -3/8(x) + 3/2, slope = -3/8

slope of a line that is parallel = -3/8

2)5x+4y = 5
  4y = -5x + 5
    y = -5/4(x) + 5/4; slope is -5/4

slope of a line that is parallel = -5/4
--------------------
perpendicular, slope is opposite and reciprocal

3)
3x+8y = 11
 8y = -3x + 11
   y = -3/8(x) + 11/8. slope = -3/8
slope of perpendicular line = 8/3

4)
x = -7, slope is undefined
so slope of perpendicular line is 0

5)
3x+2y = 12
2y = -3x + 12
 y = -3/2(x) + 6 ; slope = -3/2

5x - 6y = 8
6y = 4x - 8
  y = 2/3(x) - 4/3; slope is 2/3

slope is opposite and reciprocal, so the equals are perpendicular

6)
3x + y = 5
y = -3x + 5; slope = -3

6x + 2y = -15
2y = -6x - 15 
y = -3x - 7.5; slope = -3

both have slope = -3 so equations are parallel

3 0
3 years ago
Find the 6th term of the arithmetic sequence X – 9, -X – 11, -3.3 – 13, ...
MrMuchimi

Answer:

-13x-23

Step-by-step explanation:

Given sequence:  x-9, -x-11, -3x-13

Therefore,

  • a_1=x-9
  • a_2=-x-11
  • a_3=-3x-13

General form of an arithmetic sequence: a_n=a+(n-1)d

(where a is the first term and d is the common difference)

To find the common difference, subtract a term from the next term:

\begin{aligned}d & =a_2-a_1\\ & =(-x-11)-(x-9)\\ & = -x-11-x+9\\ & = -2x-2\end{aligned}

Therefore,

a_n & =(x-9)+(n-1)(-2x-2)

To find the 6th term, input n = 6 into the equation:

\begin{aligned}\implies a_6 & =(x-9)+(6-1)(-2x-2)\\ & = (x-9)+7(-2x-2)\\ & = x-9-14x-14\\ & = -13x-23\end{aligned}

3 0
2 years ago
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