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Mariana [72]
3 years ago
14

Plot the following ordered pairs on a graph and then determine whether or not the points represent a function.

Mathematics
2 answers:
Alex777 [14]3 years ago
5 0
The answer is :

YES: These points represent a function because none of the vertical lines I drew passed through more than one point.
snow_lady [41]3 years ago
3 0
The answer is yes i'm pretty sure
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Each of four friends orders a sweatshirt from a catalog. There are 18 colors of sweatshirts, 6 of which are all cotton and 12 of
Digiron [165]

Answer:

1/204.

Step-by-step explanation:

That would be

6/18 * 5/17 * 4/16 * 3/15

= 1/3 * 1/4 * 1/5 * 5/17

=  5/1020

= 1/204.

5 0
2 years ago
7/11 of a class walk to school. What fraction of the class did not walk to school
elena55 [62]

Answer:

4/11 of the class did not walk to school.

Step-by-step explanation:

11/11 - 7/11 = 4/11

7 0
2 years ago
9th question help ?!
Daniel [21]
Hey there! :)

You have to find the area of all of them and add it together.

Formulas:

Area of a square: l · w
Area of a triangle: (b · h) ÷ 2

Square - 

l = 3
w = 3

3 × 3 = 9

Triangle - 

b = 3
h = 3

(3 × 3) ÷ 2
    9  ÷    2   = 4.5

There are 4 triangles

4.5 × 4 = 18

9 + 18 = 27

The surface area ⇒ 27 cm²



5 0
3 years ago
(c). Under a set of controlled laboratory conditions, the size of the population P of a certain bacteria culture at time t (in s
Bezzdna [24]

(i) Since P(t) gives the population of the culture after t seconds, the population after 1 second is

P(1) = 3•1² + 3e¹ + 10 = 13 + 3e ≈ 21.155

In Mathematica, it's convenient to define a function:

P[t_] := 3t^2 + 3E^t + 10

(E is case-sensitive and must be capitalized. Alternatively, you could use Exp[t]. You can also specify that the argument t must be non-negative by entering a condition via P[t_ ;/ t >= 0], but that's not necessary.)

Then just evaluate P[1], or N[P[1]] or N <at symbol> P[1] or P[1] // N to get a numerical result.

(ii) The average rate of change of P(t) over an interval [a, b} is

(P(b) - P(a))/(b - a)

Then the ARoC between t = 2 and t = 6 is

(P(6) - P(2))/(6 - 2) ≈ 321.030

In M,

(P[6] - P[2])/(6 - 2)

and you can also include N just as before.

(iii) You want the instantaneous rate of change of P when t = 60 (since 1 minute = 60 seconds). Differentiate P :

P'(t) = 6t + 3e^t

Evaluate the derivative at t = 60 :

P'(60) = 6•60 + 3e⁶⁰ = 360 + 3e⁶⁰

The approximate value is quite large, so I'll just leave its exact value.

In M, the quickest way would be P'[60], or you can differentiate and replace (via ReplaceAll or /.) t with 60 as in D[P[t], t] /. t -> 60.

5 0
3 years ago
HELP PLSSS I'm Desperate
Arisa [49]

Answer: 27 33 15 90

Step-by-step explanation: 1 yard is 3 feet

7 0
3 years ago
Read 2 more answers
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