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3241004551 [841]
3 years ago
7

PLEASE HELP FAST!

Mathematics
1 answer:
MAXImum [283]3 years ago
5 0

Answer:

false

Step-by-step explanation:

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In a group of 35 students, 11 study both Art and Biology 11 study Biology but not Art. 10 study neither subject. Given that a ra
aliina [53]

Answer:

I did not now but anobody help you l bless you someone help

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3 years ago
Read 2 more answers
1. Rational or irrational?<br> 11/5
nignag [31]
The answer is irrational
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4. Anna, Beate and Cindy buy a bag of 30 biscuits together. They get 10 biscuits each. But Anna has paid 80 cents, Beate 50 cent
erma4kov [3.2K]

Answer:

  • Option E. 6.

Step-by-step explanation:

<u>80:50:20 or 8:5:2. 8 ÷ 15 * 30 = 16 = 16 - 10 = 6. This is the solution.</u>

  • Option A. 30 + 10 = 40. Incorrect. The solution is unequal to this.
  • Option B. 30 + 9 = 39. Incorrect. The solution is unequal to this.
  • Option C. 30 + 8 = 38. Incorrect. The solution is unequal to this.
  • Option D. 30 + 7 = 37. Incorrect. The solution is unequal to this.
  • Option E. 30 + 6 = 36. Correct. The solution equals this answer.

<u>Option E will be the answer.</u>

6 0
2 years ago
A leading bank is coming up with an investment that pays 8 percent interest compounded semiannually. What is the investment's ef
uranmaximum [27]
The effective rate is calculated in the following way:
r =  {(1 +  \frac{i}{n} )}^{n} - 1
where r is the effective annual rate, i the interest rate, and n the number of compounding periods per year (for example, 12 for monthly compounding).
our compounding period is 2 since the bank pays us semiannually(two times per year) and our interest rate is 8%
so lets plug in numbers:
r = {(1 +  \frac{8\%}{2}) }^{2}  - 1 \\ r =  {(1 +  \frac{1}{25}) }^{2}  - 1 \\ r =  \frac{676}{625}  - 1 \\ r = 0.0816 \: or \: 8.16\%
5 0
3 years ago
Twice the greater of two consecutive odd intergers is 13 less than three times the lesser. Find the intergers ​
erastova [34]

Answer:

\large\boxed{15, 16}

Step-by-step explanation:

2 consecutive integers represented as variables:

x, x + 1

Greater one: x + 1

Lesser one: x

Write as an equation

2(Greater) + 13 = 3(Lesser)

Substitute in known values

2(x + 1) + 13 = 3(x)

Multiply

2x + 2 + 13 = 3x

Subtract 2x from both sides of the equation

2 + 13 = x

Add 2 + 13 to simplify

x = 15

Lesser = x = 15

Greater = x + 1 = 15 + 1 = 16

\large\boxed{15, 16}

Hope this helps :)

3 0
3 years ago
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