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Computing the limit directly:
Alternatively, you can recognize the limit as being equivalent the derivative of <em>f(x)</em> at <em>x</em> = 2, in which case differentiating and plugging in 2 gives
<em>f'(x)</em> = 2<em>x</em> + 1 => <em>f'</em> (2) = 5
One kiloliter is equal to one hundred dekaliters. Multiply 
to get your answer :)