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2 years ago

Helppppp plzzzz I will mark brainliestttt

Mathematics

1 answer:

expeople1 [14]2 years ago

8 0

Answer:

it's a. ctxr6irx5ixtxtcycyd TY ibis4dyhugbyrobut

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Find x+y, if: 2x+3y=8 and 3x+5y=13

joja [24]

Answer is x = 1 & y = 2
the answer can be found using math-way

4 0

2 years ago

What is the mode of the following numbers? 1,2, 10, 6, 4, 4, 6, 3, 1, 4

marysya [2.9K]

Answer:

The mode of the data set is 4.

Step-by-step explanation:

Hey there!
The mode of a data set is the most commonly occurring data value in that set.

To begin, we need to organize the data set in increasing order:

1, 1, 2, 3, 4, 4, 4, 6, 6, 10

Then, we can tally the frequency of each data value occurring in the data set:

1 - II

2 - I

3 - I

4 - III

6 - II

10 - I

We can see that there are three occurrences for the data value 4 — which is the most frequent occurrence — so 4 is our answer.

Learn more about mode here: brainly.com/question/11163338

3 0

1 year ago

Read 2 more answers

For what values of x is the inequality 2/3 + x/3 >1 true?

Travka [436]

Answer:

Step-by-step explanation:

$\frac{2}{3}$ + $\frac{x}{3}$ > 1 ( multiply through by 3 to clear the fractions )

2 + x > 3 ( subtract 2 from both sides )

x > 1

6 0

2 years ago

What will be the coordinates of N after a 90° counterclockwise rotation around the origin?

USPshnik [31]

Answer:

A. (-7,-3)

D.(-3,-7) If clockwise

4 0

2 years ago

The number of typing errors made by a typist has a Poisson distribution with an average of seven errors per page. If more than s

Aleks [24]

Answer:

0.599 is the probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

We are given the following in the question:

The number of typing errors made by a typist has a Poisson distribution.

$\lambda =7$

The probability is given by:

$P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}$

We have to find the probability that a randomly selected page does not need to be retyped

P(less than or equal to 7 mistakes in a page)

$P( x \leq 7) = P(x =1) + P(x=1) +...+ P(x=6) + P(x = 7)\\\\= \displaystyle\frac{7^0 e^{-7}}{0!} + \displaystyle\frac{7^1 e^{-7}}{1!} +...+ \displaystyle\frac{7^6 e^{-7}}{6!} + \displaystyle\frac{7^7 e^{-7}}{7!} \\\\= 0.59871\approx 0.599$

Thus, 0.599 is the probability that a randomly selected page does not need to be retyped.

4 0

3 years ago