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1 year ago

Question

Mathematics

1 answer:

navik [9.2K]1 year ago

5 0

Answer:

162 units^2

Step-by-step explanation:

add all of the areas of the sides

2 ( 3 x 7) + 2 ( 3 x 6) + 2 ( 6 x 7 ) = 162 units^2

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PLSS WHAT IS THE ANSWER

Ket [755]

It’s negative by the looks of it.

If you solve it you get -2.5

I hope it’s correct!

6 0

1 year ago

Read 2 more answers

Which expression is equivalent

Tatiana [17]

Given expression is

$\sqrt[4]{\frac{16x^{11}y^8}{81x^7y^6}}$

Radical is fourth root

first we simplify the terms inside the radical

$\frac{x^{11}}{x^7}=x^4$

$\frac{y^(8)}{y^6}=y^2$

So the expression becomes

$\sqrt[4]{\frac{16x^4y^2}{81}}$

Now we take fourth root

$\sqrt[4]{16} = 2$

$\sqrt[4]{81} = 3$

$\sqrt[4]{x^4} = x$

We cannot simplify fourth root (y^2)

After simplification , expression becomes

$\frac{2x\sqrt[4]{y^2}}{3}$

Answer is option B

8 0

2 years ago

Find the equation of the line using the point-slope formula. Write the final equation using slope-intercept form. (1,2) with a s

Lilit [14]

Answer:

$y-2=\displaystyle -\frac{3}{4}(x-1)$

$y=\displaystyle -\frac{3}{4}x+\frac{11}{4}$

Step-by-step explanation:

Hi there!

Point-slope form: $y-y_1=m(x-x_1)$ where m is the slope of the line and $(x_1,y_1)$ is a given point

Given that the slope is -3/4, we can plug it into $y-y_1=m(x-x_1)$ as m:

$y-y_1=\displaystyle -\frac{3}{4}(x-x_1)$

We can also plug in the given point (1,2):

$y-2=\displaystyle -\frac{3}{4}(x-1)$

Slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

To write the equation in slope-intercept form, isolate y:

$y-2=\displaystyle -\frac{3}{4}(x-1)\\\\y=\displaystyle -\frac{3}{4}(x-1)+2\\\\y=\displaystyle -\frac{3}{4}x+\frac{3}{4}+2\\\\y=\displaystyle -\frac{3}{4}x+\frac{11}{4}$

I hope this helps!

8 0

2 years ago

I need help asap I have a problem I need the answer for this please its 4 -2 over 4 as a fraction =6

Alex

Answer:

its 2/6 simplified. lol

Step-by-step explanation:

3 0

2 years ago

What are the zeros of the function? what are their multiplicities? f(x)=x^4-4x^3+3x^2

-Dominant- [34]

Since each term contains x, x= 0 is one answer Also as x^2 is a factor it has duplicity 2.
Factoring:-

x^2 (x^2 - 4x + 3) = 0
x^2( x - 3)(x - 1) = 0

so x = 3 and x = 1 are also zeros

Answer:- x = 0 (duplicity 2), x = 1 and x = 3.

4 0

2 years ago