Question

Don't just say the answer, please show how you got it so I can know for further use​

Answer 1

Answer:

C

Step-by-step explanation:

We have the equation:

$x^2-6x=10$

We can subtract 10 from both sides:

$x^2-6x-10=0$

Since this equation isn't factorable, we can use the quadratic formula:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a = 1, b = -6, and c = -10.

Substitute:

$\displaystyle x=\frac{-(-6)\pm\sqrt{(-6)^2-4(1)(-10)}}{2(1)}$

Simplify:

$\displaystyle x=\frac{6\pm\sqrt{76}}{2}$

Note that:

$\sqrt{76}=\sqrt{4\cdot 19}=2\sqrt{19}$

Hence:

$\displaystyle x=\frac{6\pm2\sqrt{19}}{2}=3\pm\sqrt{19}$

Therefore, our answer is C.