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Naddik [55]
3 years ago
7

Sara needs 1/3 of a yard of ribbon to make a bow. She has 10 yards of ribbon. How many bows can she make?

Mathematics
1 answer:
storchak [24]3 years ago
8 0

Answer:

30 Bows

Step-by-step explanation:

Every yard is 3 feet, and each bow calls for 1/3 of a yard, so a foot per bow.

So you can make 10 yards, 30 feet by multiplying by 3, and then its pretty straight forward from there. 30 / 1 = 30 Bows

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Can someone explain HOW to simplify this algebraic fraction, as in tell me why and what I need to do for each step : 1-n/n^2-1
Andreyy89

- I’m assuming the expression implies the following:

(1-n)/(n^2 - 1)

The steps goes as follows:

= -(n-1)/(n^2-1) (factored a negative out)
= -(n-1)/[(n+1)(n-1)] (Factored denominator into a difference of squares, but don’t just blindly accept the fact, expand it and you should get the original denominator)

At this point, the (n-1) terms cancel, as you should know: a real number, besides 0, over itself is 1.

= -1/(n+1) , which is the answer

Note: You could also see it as 1/-(n+1) or 1/(-n-1)
8 0
2 years ago
A ball has a radius of 18 cm.
jok3333 [9.3K]
Hello there.
<span>
A ball has a radius of 18 cm.

What is the approximate volume of the ball?

Use 3.14 to approximate pi. Round to the nearest hundredth if necessary.
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Answer: <span>24416.64</span>
4 0
2 years ago
Read 2 more answers
Question 3
hoa [83]

answer is (-7,2)

y = -x -5

y= x+9

Both equations have y on the left hand side

So we equate both equations

We replace -x-5 for  y in the second equation

-x -5 = x+9

Subtract x on both sides

-2x -5 = 9

Now add 5 on both sides

-2x = 14

Divide by -2 from both sides

x = -7

Now plug in -7 for x in the first equation

y = -x -5

y = -(-7)  -5= 7-5 = 2

So answer is (-7,2)

4 0
3 years ago
Read 2 more answers
What are the coordinates of the point (-1,9) after a clockwise rotation of 90 degree about the origin
Elina [12.6K]

The rule for clockwise rotation of 90 degrees about the origin is (-y, x).

So (-1,9) would now be (-9,1).

Hope this Helps!!

7 0
2 years ago
As cars drive up a ramp at a multi-storey car park they go up 2 meters. the length of the ramp is 10 meters. find the angle betw
daser333 [38]
This is a right angle triangle problem
drawing a vertical line at from the point where the ramp touches the car park leaves a right angle triangle with the
opposite being 2m
hypothenus being 10m
adjacent unknown
we could use sine
SineO equal to opposite over hypothenus
SineO equal to 2/10
SineO equal to 0.2
O equal to Sine^1(0.2)
O equal to 11 .5
The angle between the ramp and the horizontal is 11.5 degrees
7 0
2 years ago
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