Answer:
we reject H₀
Step-by-step explanation: Se annex
The test is one tail-test (greater than)
Using α = 0,05 (critical value ) from z- table we get
z(c) = 1,64
And Test hypothesis is:
H₀ Null hypothesis μ = μ₀
Hₐ Alternate hypothesis μ > μ₀
Which we need to compare with z(s) = 2,19 (from problem statement)
The annex shows z(c), z(s), rejection and acceptance regions, and as we can see z(s) > z(c) and it is in the rejection region
So base on our drawing we will reject H₀
Use the substitution method for x
y= 4(-2)-1
y= -8-1
y= -9
Answer is y=-9
Answer:
19
Step-by-step explanation:
4 + [(16 - 4) + (12 -9)]
Using PEMDAS, first solve the parentheses.
16-4 is 12 and 12-9 is 3
Rewrite the expression
4+(12+3)
12+3 is 15
4+15
19.
All you have to do here is some simplifying.
6/12 = what
6 divided by 12 = 1/2
1/2 = 2/4
There! We have our missing value
6/12 = 2/4
Answer: c = 4