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san4es73 [151]
2 years ago
11

I need help with this question

Mathematics
1 answer:
Dimas [21]2 years ago
4 0

Answer:

Step-by-step explanation:

10+18+25+27+35+50=165

n=6

mean =165/6=27.5

x   x- mean    (x-mean)²

10     -17.5          306.25

18      -9.5            90.25

25     -2.5              6.25

27     -0.5              0.25

35      7.5            56.25

50   22.5          506.25

      _____      ________

sum     0             965.5

       _____     _________

standard deviation

=\sqrt{\frac{sum}{n-1} } \\=\sqrt{\frac{965.5}{5} } \\=\sqrt{193.1} \\\approx 13.896

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Please help i put max points for u!!
jek_recluse [69]

Answer:

Equation: y = \frac{7}{4} x

21/2 cups of water

Step-by-step explanation:

Plug in 7 as y and 4 as x

7 = 4k

Find k

k = 7/4

Then plug k into th equation

y = 7/4 x

For the second part of the question:

Plug in x which is 6 into the bolded equation.

y = (7/4)(6) = 42/4 = 21/2 (simplified form)

21/2 cups of water

5 0
3 years ago
Read 2 more answers
Katie collects stamps. She has stamps from Canada, the U.S.A, and the rest of the world in a ratio of 1: 1.2: 1.5. She has 135 s
adoni [48]

Answer:

Step-by-step explanation:

:  I got A)90

          B)108

          C)333

              Hope that's right. I checked it 4 times.

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3 years ago
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What is the sum of 1 - 0.5 + 899
I am Lyosha [343]

Answer:

899.5

Step-by-step explanation:

8 0
3 years ago
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.6 Mbp
olga55 [171]

Answer:

a) 59.98

b) 2.99

c) 2.99

d) Significantly High

Step-by-step explanation:

Part a)

Highest speed measured = x = 75.6 Mbps

Average/Mean speed = \overline{x} = 15.62 Mbps

Standard Deviation = s = 20.03 Mbps

We need to find the difference between carrier's highest data speed and the mean of all 50 data​ speeds i.e. x - \overline{x}

x - \overline{x} = 75.6 - 15.62 = 59.98 Mbps

Thus, the difference between​ carrier's highest data speed and the mean of all 50 data​ speeds is 59.98 Mbps

Part b)

In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

\frac{59.98}{20.03}=2.99

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

z=\frac{x-\overline{x}}{s}

Using the given values, we get:

z=\frac{75.6-15.62}{20.03}=2.99

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly​ high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the  carrier's highest data speed​ is significantly higher.

3 0
3 years ago
Suppose there are 8 boys and 7 girls in a classroom. If one student is chosen at random to run a errand. What is the probability
LUCKY_DIMON [66]

Answer:

47%

Step-by-step explanation:

There are 15 total students, so find the percentage of girls out of the total students: 7/15= .466, which is about 47%. To double check, you can do the boys and make sure it adds to 100%. 8/15= .533, which is about 53%. 47+53=100. So girls are 47% and boys are 53%

4 0
3 years ago
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