Answer:
t = sqrt(500/4.9) =~ 10.1 seconds/
Answer: 10.1015 seconds (this is approximate)
Step-by-step explanation:
Use 4.9t^2 + v0t = s
a) A bolt falls off an airplane at an altitude of 500 m. Approximately how long does it take the bolt to reach the ground?
s = 4.9t^2 + v0t = 500
4.9t^2 = 500
t = sqrt(500/4.9) =~ 10.1 seconds
Part A)
v = initial velocity = 0
s = 500 = vertical distance the object travels (from plane to ground)
Plug in the given values and solve for t
4.9t^2 + v*t = s
4.9t^2 + 0*t = 500
4.9t^2 + 0 = 500
4.9t^2 = 500
t^2 = 500/4.9
t^2 = 102.04081632653
t = sqrt(102.04081632653)
t = 10.101525445522
t = 10.1015
Answer: 10.1015 seconds (this is approximate)
Answer:
No solution
Step-by-step explanation:
So we have the equation:

First, subtract 20 from both sides:

Now, we can stop. Recall that absolute value will always <em>always</em> give a positive answer.
Since this equals -16, this means that there is no solution.
And we're done!
Answer:
No.
Step-by-step explanation:
Try the vertical line test. If the lines intersect or connect at some point, then it's not a function. Do you want to practice with some Ixls to help, or use some images for reference?
Given that Trent's watch runs at half the speed it should run, this implies that
for every hour passed, his watch moves by half an hour.
Hence, for every half-hour passed, Trent's watch moves by 15 minutes.
Hence, when the real time is 10:30 am, Trent's watch will show 9:15 am.