Question

12 G of carbon react with 16 G of oxygen how much carbon monoxide is formed ​

Answer 1

Answer:

28 g CO

Explanation:

First convert grams to moles.

1 mole C = 12.011 g (I'm just going to round to 12 for the sake of this problem)

12 g C • $\frac{1 mol C}{12 g C}$ = 1 mol C

1 mol O = 15.996 g (I'm just going to round to 16)

16 g O • $\frac{1 mol O}{16 g O}$ = 1 mol O

So the unbalanced equation is:

$C + O_{2}$ -> $CO$ (the oxygen has a 2 subscript because it is part of HONClBrIF meaning when not in a compound these elements appear in pairs - called diatomic elements)

The balanced equation is:

$2 C + O_2$ -> $2 CO$

However, carbon is the limiting reactant in this equation and two moles cannot react because only 12 g (1 mole) are present. Therefore, use the equation

$C + \frac{1}{2} O_2$ -> $CO$.

1 mole of CO is formed, therefore 12 g + 16 g = 28 g CO.