Using the rules below,select ALL compounds that are soluble
1 answer:
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Answer:
Sn2 mechanism reaction
Explanation:
In this case, we have a <u>primary substrate</u> (1-bromo-3,3-dimethylbutane). Because the <u>leaving grou</u>p "Br" is bonded to a <u>primary carbon</u>. Additionally, the nucleophile will come from the "NaI" (sodium iodide). This is an <u>ionic compound</u>, so, in solution, a cation and an anion would be produced. The anion would be the <u>nucleophile</u>.
Due to the primary substrate, we will have an <u>Sn2 reaction</u>. So, the attack of the nucleophile and the removal of the leaving group will take place in <u>1 step</u>. Producing a <u>"transition state"</u> and finally and the final product (1-iodo-3,3-dimethylbutane).
See figure 1
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