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skad [1K]
3 years ago
9

Brainliest for an answer!

Chemistry
1 answer:
Degger [83]3 years ago
5 0

The volume of H₂ : = 15.2208 L

<h3>Further explanation</h3>

Given

Reaction

2 As (s) + 6 NaOH (aq) → 2 Na₃AsO₃ (s) + 3 H₂ (g)

34.0g of As

Required

The volume of H₂ at STP

Solution

mol As (Ar = 75 g/mol) :

= mass : Ar

= 34 g : 75 g/mol

= 0.453 mol

From the equation, mol ratio As : H₂ = 2 : 3, so mol H₂ :

=3/2 x mol As

=3/2 x 0.453

= 0.6795

At STP, 1 mol = 22.4 L, so :

= 0.6795 x 22.4 L

= 15.2208 L

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What is true for all exergonic reactions?
vovangra [49]

Answer:

The reaction proceeds with a net release of free energy.

Explanation:

Exergonic reactions: It is known as the chemical reaction where the change in the free energy is occur negative or there is a net release of free energy, and indicating a spontaneous reaction. For the processes this takes place under constant temperature, and pressure conditions.

The Gibbs free energy is used whereas the processes which takes place under constant volume, and temperature conditions, and their Helmholtz energy is used. Cellular respiration is the example of an exergonic reaction.

4 0
3 years ago
What is the volume occupied by 112.0 grams of mercury
-BARSIC- [3]

Answer:

V= 8.235 ml

Explanation:

The man above me copied me from the comments

I did it >:C

8 0
3 years ago
Consider the combustion of butane gas:C₄H₁₀(g ) + 13/2O₂(g) → 4CO₂(g) + 5H₂O(g) (b) Calculate ΔG° by two different methods.
kompoz [17]

The value of ΔG° (gibbs free energy change) is -2703kj and -2657kj.

Given ,

combustion reaction of butane :

C4H10(g) + 13/2O2 (g) →4CO2(g) + 5H2O(g)

Method-1 :

We know ,

ΔGrxn = sum of ΔG (product ) - sum of ΔG (reactant )

= [4 × (-394.4) + 5×(-228.6) ] - [1×(-16.7)]

ΔGrxn = -2720.6kj

Method-2 :

We know ,

ΔG = ΔH -TΔS

T =298K

Thus , ΔHrxn = sum of ΔH (product ) - sum of ΔH (reactant )

= [4×(-393.5) + 5×(-241.8) ] - [ 1×(-126)]

ΔHrxn = -2657kj

ΔSrxn = sum of ΔS (product ) - sum of ΔS( reactant )

= [ 4×(213.7) + 5×188.7 ] - [ 13/2 ×205 + 1×310 ]

ΔSrxn = 155.8j/K

ΔSrxn = 0.1558kj/K

Thus , ΔG = ΔH - TΔS

= -2657 - ( 298 × 0.1558kj/K )

ΔG = -2720kj

Hence , the value of ΔG is -2703kj .

Learn more combustion reaction here :

brainly.com/question/13251946

#SPJ4

7 0
2 years ago
When 64.0 g of methanol (CHOH) is burned, 1454 kJ of energy is produced. What is the heat of combustion for methanol?
andreev551 [17]

 The heat  of combustion  for  methanol   is 727  kj/mol


    <em><u>calculation</u></em>

 calculate the moles  of methanol (CH3OH)

moles = mass/molar  mass

molar mass of methanol =  12 +( 1 x3)  +16 + 1= 32 g /mol

moles is therefore= 64.0 g / 32 g/mol =  2 moles


Heat of combustion  is therefore = 1454 Kj / 2 moles =  727  Kj/mol

6 0
3 years ago
Write the balanced chemical reaction,<br> Please help
solmaris [256]

Answer:

Ca2O2

Explanation:

Ca + O2 --> Ca2O2

O2 = -2

Ca = -1 so need 2 of it

5 0
2 years ago
Read 2 more answers
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