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anyanavicka [17]
3 years ago
6

Based on the information in the graph, what is the relationship between air temperature and the amount of water vapor that the a

ir can hold? *
1 point
The higher the temperature the less water vapor it can hold
The higher the temperature the more water vapor it can hold
The temperature has noting to do with the amount of water vapor it can hold
Chemistry
1 answer:
NeTakaya3 years ago
5 0

Answer:

1 i think

Explanation:

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Hey can someone at least answer one of these please.
Vlada [557]

Answer:

whats the question

Explanation:

4 0
2 years ago
What is the difference between the 3p sublevel and the 4p sublevel?<br><br> On the periodic table
statuscvo [17]
The p sublevels are named 2p, 3p, and 4p since the p sublevel appears only starting the 2nd level. By the Aufbau principle, 3p will be filled first before 4p. This is because of the energy present on the level. 

Each of the p sublevel has 3 orbitals, allowing them to contain 6 electrons as each orbital may hold two. 
6 0
2 years ago
Neutrons have neither charge nor mass.<br> TRUE<br> FALSE
iren2701 [21]

Answer:

FALSE

nuetrons do indeed have no charge, however they are nearly 2000 more times massive than electrons.

7 0
2 years ago
5Br−+BrO3−+6H+→3Br2+3H2O
sashaice [31]

Explanation :

The balanced chemical reaction is,

5Br^-+BrO_3^-+6H^+\rightarrow 3Br_2+3H_2O

The expression for the rates of consumption of the reactants are:

The rate of consumption of Br^- = -\frac{1}{5}\frac{d[Br^-]}{dt}

The rate of consumption of BrO_3^- = -\frac{d[BrO_3^-]}{dt}

The rate of consumption of H^+ = \frac{1}{6}\frac{d[H^+]}{dt}

The expression for the rates of formation of the products are:

The rate of consumption of Br_2 = +\frac{1}{3}\frac{d[Br_2]}{dt}

The rate of consumption of H_2O = +\frac{1}{3}\frac{d[H_2O]}{dt}

5 0
2 years ago
How much energy is added to change 180g of liquid water to gas at 100 degrees Celsius
Finger [1]

Answer:

40.7 kJ  

Step-by-step explanation:

The formula for the heat, q, needed to evaporate a liquid is

q = mΔHvap


<em>Data:  </em>

        m = 180 g

ΔHvap = 2260 J/g

<em>Calculation: </em>

q = 180 g × 2260 /1

q = 40 700 J = 40.7 kJ

7 0
2 years ago
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