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Alex777 [14]
3 years ago
15

Rihanna planned a rectangular courtyard for a park and made a scale drawing using inches as the unit of measurement. She origina

lly planned for the length of the actual courtyard to be 54 feet, but she decided to change it to 72 feet. If the length of the courtyard is 18 inches in her scale drawing, which statement about the change of scale is true?
One inch represented 1 foot in the first scale, but now 1 inch represents 4 feet in the second scale.
One inch represented 4 feet in the first scale, but now 1 inch represents 3 feet in the second scale.
One inch represented 54 feet in the first scale, but now 1 inch represents 72 feet in the second scale.
One inch represented 3 feet in the first scale, but now 1 inch now represents 4 feet in the second scale.
Mathematics
2 answers:
Romashka [77]3 years ago
7 0

Answer: One inch represented 3 feet in the first scale, but now 1 inch now represents 4 feet in the second scale.

Oksana_A [137]3 years ago
4 0
There are 375 audience tickets available for each taping of the Win It All game show.  If 204 shows are taped each year, how many tickets are there in all? There are
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Which of the following is true of algorithms and heuristics for solving real-life problems?
professor190 [17]

Answer: Under the given option, the following is true of algorithms and heuristics for solving real-life problems: <u><em>Heuristics are shortcut strategies. </em></u>

Algorithms are known as step by step plan of action for resolving a issue. It leads to a specific solution, methodically.

whereas;

Heuristics are known as short‐cut, step‐saving reasoning scheme or generalization that bring forth a solution speedily but possibly with an error.

<u><em>Therefore, the correct option is (a)</em></u>

4 0
3 years ago
Use series to verify that<br><br> <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{
SVETLANKA909090 [29]

y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\

\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\

This shows that y' = y is true when y = e^x

-----------------------

  • Note 1: A more general solution is y = Ce^x for some constant C.
  • Note 2: It might be tempting to say the general solution is y = e^x+C, but that is not the case because y = e^x+C \to y' = e^x+0 = e^x and we can see that y' = y would only be true for C = 0, so that is why y = e^x+C does not work.
6 0
3 years ago
Kristi got a 7/23 balloon mortgage and her initial payments were $895. She decided to refinance her balloon payment with a 30-ye
Nookie1986 [14]

Answer: 389,460 - Apex

6 0
4 years ago
Read 2 more answers
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Snezhnost [94]

Answer:

See below.

Step-by-step explanation:

The probability of an event happening is a number from 0 to 1. A probability of 1 means the event will definitely happen. A probability of 0 means there is no way the event will happen. There is no probability of 50.

6 0
3 years ago
Solve and graph: 7x-6&gt;22<br>(pls explain your answer, im confused on this)​
grandymaker [24]

Answer:

x>4

Step-by-step explanation:

Solving an inequality is very similar to solving an equation:

Given: 7x-6>22

Add 6 to both sides: 7x>28

Divide both side by 7: x>4

x>4 means that all x-values that are greater than 4 will work. Therefore you would write an open dot at x=4 on the number line to show that 4 isn't included, and draw an arrow going right to show all possible solutions greater than 4.

6 0
3 years ago
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