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Alex777 [14]
2 years ago
15

Rihanna planned a rectangular courtyard for a park and made a scale drawing using inches as the unit of measurement. She origina

lly planned for the length of the actual courtyard to be 54 feet, but she decided to change it to 72 feet. If the length of the courtyard is 18 inches in her scale drawing, which statement about the change of scale is true?
One inch represented 1 foot in the first scale, but now 1 inch represents 4 feet in the second scale.
One inch represented 4 feet in the first scale, but now 1 inch represents 3 feet in the second scale.
One inch represented 54 feet in the first scale, but now 1 inch represents 72 feet in the second scale.
One inch represented 3 feet in the first scale, but now 1 inch now represents 4 feet in the second scale.
Mathematics
2 answers:
Romashka [77]2 years ago
7 0

Answer: One inch represented 3 feet in the first scale, but now 1 inch now represents 4 feet in the second scale.

Oksana_A [137]2 years ago
4 0
There are 375 audience tickets available for each taping of the Win It All game show.  If 204 shows are taped each year, how many tickets are there in all? There are
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g A certain financial services company uses surveys of adults age 18 and older to determine if personal financial fitness is cha
leva [86]

Answer:

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}  

z=\frac{0.410-0.35}{\sqrt{0.385(1-0.385)(\frac{1}{1000}+\frac{1}{700})}}=2.502    

p_v =2*P(Z>2.502)= 0.0123    

Comparing the p value with the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to to reject the null hypothesis, and we can say that the proportion analyzed is significantly different between the two groups at 5% of significance.    

Step-by-step explanation:

Data given and notation    

X_{1}=410 represent the number of people indicating that their financial security was more than fair for the recent year

X_{2}=245 represent the number of people indicating that their financial security was more than fair for the year before

n_{1}=1000 sample 1 selected  

n_{2}=700 sample 2 selected  

p_{1}=\frac{410}{1000}=0.410 represent the proportion estimated of indicating that their financial security was more than fair this year

p_{2}=\frac{245}{700}=0.35 represent the proportion estimated of indicating that their financial security was more than fair the year before

\hat p represent the pooled estimate of p

z would represent the statistic (variable of interest)    

p_v represent the value for the test (variable of interest)  

\alpha significance level given  

Concepts and formulas to use    

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

We need to apply a z test to compare proportions, and the statistic is given by:    

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{410+245}{1000+700}=0.385  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.    

Calculate the statistic  

Replacing in formula (1) the values obtained we got this:    

z=\frac{0.410-0.35}{\sqrt{0.385(1-0.385)(\frac{1}{1000}+\frac{1}{700})}}=2.502    

Statistical decision  

Since is a two sided test the p value would be:    

p_v =2*P(Z>2.502)= 0.0123    

Comparing the p value with the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to to reject the null hypothesis, and we can say that the proportion analyzed is significantly different between the two groups at 5% of significance.    

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3 years ago
This is a word problem: You are riding a ski lift at a position 57 feet off the ground. You spot one of your friends skiing belo
Varvara68 [4.7K]

Answer:6 minutes

Step-by-step explanation:

6 0
3 years ago
Suppose that X1 and X2 are independent random variables each with a mean μ and a variance σ^2. Compute the mean and variance of
Deffense [45]

Mean:

E[Y] = E[3X₁ + X₂]

E[Y] = 3 E[X₁] + E[X₂]

E[Y] = 3µ + µ

E[Y] = 4µ

Variance:

Var[Y] = Var[3X₁ + X₂]

Var[Y] = 3² Var[X₁] + 2 Covar[X₁, X₂] + 1² Var[X₂]

(the covariance is 0 since X₁ and X₂ are independent)

Var[Y] = 9 Var[X₁] + Var[X₂]

Var[Y] = 9σ² + σ²

Var[Y] = 10σ²

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Fill in the blank to find the y-intercept of-x+2y=10
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I think x is 20 I’m not sure tho since it would come out as -10 instead of positive
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Remember the type of word problems that have been posted this week. Now it's your turn. Create a word problem that can represent
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What is two times something and then add 6 to it

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