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spin [16.1K]
3 years ago
5

The area of a rectangular deck can be modeled by f(x) = 2x3 + 30x2 – 6x – 90. If x + 15 represents the width, which expression r

epresents the length?
Mathematics
2 answers:
zhannawk [14.2K]3 years ago
4 0
Divide f(x) by x + 15

this comes to 2x^2 - 6  which represents the length
vodka [1.7K]3 years ago
4 0
Area of ​​a rectangle =  length * width
<span>
f(x) = 2x</span>³ + 30x² – 6x – 90
f(x) = 2(x³ + 15x² – 3x – 45)
f(x) = 2(x²(x + 15) – 3(x+15))
f(x) = 2(x²-3)(x+15)

If <span>width </span>= x+15, then 
length = 2(x²-3) = 2x²-6
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Can you answer this Algebra question please?<br> (Just A, thank you).
Eduardwww [97]

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The fraction 2/5 is equivalent to 0.4 and 2 40%. Write 0.4 and 40% as unreduced fractions.
Bezzdna [24]
0.4 = 4/10
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3 years ago
Simplify: 12 + 2 x 3 + ( 43 - 12)<br> 68<br> 54<br> 70<br> 18
Stolb23 [73]
I got 49 hope that will help.
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3 years ago
Find the length of the third side. If necessary, round to the nearest tenth. 10 24
galben [10]

Answer:

26 units

Step-by-step explanation:

Pythagoras' Theorem: \sf a^2+b^2=c^2

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

Given

  • a = 10
  • b = 24

Substitute the given values into the formula and solve for c:

\sf \implies 10^2+24^2=c^2

\sf \implies c^2=676

\sf \implies c=\pm\sqrt{676}

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2 years ago
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Your digital camera has a 512 megabyte memory card. You take pictures at two resolutions, a low resolution requiring 4 megabytes
____ [38]

One possible answer is 8H + 4L = 512

=======================================================

Explanation:

  • H = number of high resolution photos
  • L = number of low resolution photos

H and L are placeholders for positive whole numbers, or 0 could replace either variable.

1 high resolution photo takes up 8 mb of space, so H of them take up 8H megabytes of space.

1 low resolution photo takes up 4 mb of space, so L of them take up 4L megabytes.

Overall, the two types of photos take up 8H+4L megabytes, which is equal to 512 since that's the max capacity. That leads to the equation 8H+4L = 512

----------------------------------

Extra info:

There are other ways to express the equation 8H+4L = 512. We could divide each part by 4 to get 2H+L = 128, but I think this equation loses its descriptive quality in a way. We no longer can see that each high resolution photo takes up 8 megabytes (instead we might mistakenly think only 2 megabytes are used per high resolution photo). A similar mistake may happen with the low resolution photos also.

The equation 2H+L = 128 can be rearranged into L = -2H+128 when solving for L.

6 0
3 years ago
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