Answer:
The volume of cube C is
Step-by-step explanation:
step 1
Find the diameter of sphere B
we know that
When a cube is inscribed in a sphere, the long diagonal of the cube is a diameter of the sphere
Let
L ----> the length side of cube A
d ----> the diagonal of the base of cube A
D ---> the long diagonal of cube A
Find the diagonal of the base of cube A
Applying the Pythagorean Theorem
we have
substitute
Find the long diagonal of cube A
Applying the Pythagorean Theorem
substitute
step 2
we know that
If sphere B is inscribed in cube C, then the length side of cube C is equal to the diameter of sphere B
Let
c ----> the length side of cube C
we have that
The volume of cube C is equal to
substitute
Step-by-step explanation:
hope you understand I've shown the process in the picture.
I think it’s c but I don’t know
Answer: d. None of the above are correct.
Step-by-step explanation: Noise is a superfluous random alteration in an eletrical signal. There are different types of noises created by different devices and process. Thermal noise is one of them. It is unavoidable because is created by the agitation of the charge carriers, due to temperature, inside an eletrical conductor at equilibrium and is present in all eletrical circuits.
The formula to find the thermal noise power (N) is: N = .T.B, where:
is Boltzmann constant (1.38.J/K);
T is temperature in Kelvin;
B is the bandwith;
Calculating the thermal noise power:
N = 1.38.·292·40
N = 16118.4. dBm
The thermal noise power [N] = 16118.4. dBm
Noise power density or simply Noise density (N₀) is the noise power per unit of bandwith and its SI is watts per hertz.
For thermal noise, N₀ = kT, where
<em>k </em>is the Boltzmann constant in J/K;
T is the receiver system noise temperature in K;
N₀ = 1.38. . 292
N₀ = 402.96. W/Hz
The thermal noise power density [N₀] = 402.96. W/Hz