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3 years ago

Pls help!!

Mathematics

1 answer:

BigorU [14]3 years ago

5 0

Answer:

105 sq ft.

Step-by-step explanation:

LA = slant height time perimeter of the base divided by 2.

Perimeter = 5(6) = 30

LA = 7(30)/2 = 105 sq ft.

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What is 2-2??<br>I will give brainliest

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Step-by-step explanation:

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3 years ago

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What is the length of a line segment on the coordinate plane with end point (3,5) and (6,8) to the nearest tenth

yan [13]

Answer:

Step-by-step explanation:

Use the distance formula for coordinate geoemetry and the fact that x1 = 3, y1 = 5, x2 = 6 and y2 = 8 to fill in the formula:

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

fills in accordingly:

$d=\sqrt{(6-3)^2+(8-5)^2}$

which simplifies a bit to

$d=\sqrt{(3)^2+(3)^2}$

which is

$d=\sqrt{18}$

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3 years ago

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If you can help me that would be great the instructions are to factor these polynomial Don’t answer just to get pointsNO LINKS!!

natima [27]

Answer:

3. 3(x+y)(x-y)

4. (y²+4)(y+2)(y-2)

5. 2(3x+1)(x+2)

Step-by-Step:

3. 3(x²-y²) = 3(x+y)(x-y)

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4 0

3 years ago

Given:

oksian1 [2.3K]

Answer:

9 units

Step-by-step explanation:

By the midsegment theorem,

$AB=\dfrac{KN+LM}{2}$

Since the ratio $LM:KN=1:5,$ then $LM=x,\ KN=5x$ and

$18=\dfrac{x+5x}{2}\\ \\18=\dfrac{6x}{2}\\ \\18=3x\\ \\x=6\\ \\LM=6\ units\\ \\KN=30\ units$

Draw two heights LE and MF. Quadrilateral ELMF is a rectangle, then EF = LM = 6 units.

Trapezoid KLMN is isosceles trapezoid (KL = MN), then KE = FN and

$KE=FN=\dfrac{KN-EF}{2}=\dfrac{30-6}{2}=12\ units$

Consider right triangle KLE. By the Pythagorean theorem,

$KL^2=LE^2+KE^2\\ \\15^2=LE^2+12^2\\ \\LE^2=15^2-12^2\\ \\LE^2=225-144=81\\ \\LE=9\ units$

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3 years ago

(08.02)a pair of equations is shown below. 3x − y = 9 y = −2x + 11 if the two equations are graphed, at what point do the lines

mixas84 [53]

3x - y = 9
y = -2x + 11

3x - (-2x + 11) = 9
3x + 2x - 11 = 9
3x + 2x = 9 + 11
5x = 20
x = 20/5
x = 4

y = -2x + 11
y = -2(4) + 11
y = -8 + 11
y = 3

solution (where the lines intersect) is (4,3)

8 0

4 years ago

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