Question

What would 'x' be in the equation -3(x-2)=6?

Answer 1

Answer:

$\boxed {\boxed {\sf x=0}}$

Step-by-step explanation:

To solve this equation, we must isolate the variable (x) using inverse operations.

$-3(x-2)=6$

x-2 is being multiplied by -3. The inverse operation of multiplication is division, so we divide both sides by -3.

$-3(x-2)/-3= 6/-3\\(x-2)=6 /-3 \\(x-2)= -2$

2 is being subtracted from x. The inverse operation of subtraction is addition, so add 2 to both sides of the equation.

$x-2+2=-2+2\\x=-2+2\\x=0$

In this equation, x is equal to 0.