Answer:
113 feet
Step-by-step explanation:
I will assume you meant h = -4.9t^2 + 135; "t2" is incorrect.
To answer this question, to find the height of the ball after 2.1 seconds, substitute 2.1 for t in the above equation:
h(2.1) = -4.9(2.1)^2 + 135. This becomes -21.6 + 135, or 113.4.
The closest result to the height of the ball after 2.1 seconds is 113 feet.
1.a. correct
1.b. 
1.c. correct
1.d. 
2.a. 7 - x + 3w - 9
Terms: 7, -x, 3w, -9
Variables: x, w
Coefficients: -1, 3
Constants: 7, -9
2.b. -g + 8k - 3 - 7
Terms: -g, 8k, -3, -7
Variables: g, k
Coefficients: -1, 8
Constants: -3, -7
3.a. correct
3.b. correct
3.c. -5+ 4x = -x
4.a. 4(2x + 3) = 8x + 12
4.b. -2(3x + 4) = -6x - 8
4.c. -5(2x - 3) = -10x + 15
Answer:
24
Step-by-step explanation:
SA= 6a sqaured
a is the edge
a=2
a squared = 4
SA=6(4)
SA=24
Answer:
For this case we have this function given:

In order to find the domain we need to find the possible values of x that the function can assume.
And we know that for this case the logarithm for 0 or neagtive numbers is not possible to calculate it, so then we can say that the domain for this case is:

And we can write this in formal notation as:
![D = [ X \in R | X>0]](https://tex.z-dn.net/?f=%20D%20%3D%20%5B%20X%20%5Cin%20R%20%7C%20X%3E0%5D)
And the best answer for this case would be:
all real numbers greater than 0
Step-by-step explanation:
For this case we have this function given:

In order to find the domain we need to find the possible values of x that the function can assume.
And we know that for this case the logarithm for 0 or neagtive numbers is not possible to calculate it, so then we can say that the domain for this case is:

And we can write this in formal notation as:
![D = [ X \in R | X>0]](https://tex.z-dn.net/?f=%20D%20%3D%20%5B%20X%20%5Cin%20R%20%7C%20X%3E0%5D)
And the best answer for this case would be:
all real numbers greater than 0
Answer: 
Step-by-step explanation:
Given : Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed and that σ = 4 psi.
A random sample of 8 specimens is tested, and the average breaking strength is found to be 98 psi.
i.e. n= 8 and 
Critical value for 95% confidence = 
Confidence interval for population mean :-

i.e. 



Hence, a 95% two-sided confidence interval on the true mean breaking strength. = 