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murzikaleks [220]
3 years ago
12

Sodium (Na) and potassium (K) are in the same group in the periodic table. Sodium is in the 11th position. How many valence elec

trons does potassium have?
A. 0
B. 1
C. 9
D. 11
Chemistry
2 answers:
daser333 [38]3 years ago
6 0

Answer: B: 1

Explanation: PLATO

Dafna1 [17]3 years ago
4 0

potassium is just below the sodium in periodic table in s group !

so the valence electron of sodium and potassium is same and that is 1

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10 points<br><br> How many more oxygen atoms are in 3Mg3(PO4)2 than in 4Al2O3?
Feliz [49]

Answer:

12 more oxygen

Explanation:

An atom is the smallest particles that can take part in a chemical reaction

The given compounds are:

        3Mg₃(PO₄)₂  

 Number of oxygen atoms  = 3[2 x 4]  = 24 oxygen atoms

For;

             4Al₂O₃;

   Number of oxygen atoms  = 4 x 3  = 12 oxygen atoms

In   3Mg₃(PO₄)₂  , there are 24  - 12  = 12 more oxygen atoms than in  4Al₂O₃;

6 0
3 years ago
Read 2 more answers
the chemical compound C2F4 is used to make PTEE (Teflon). How manyC2F4 molecules are in 485 kilograms of this material?
monitta

Answer:

molecules=2.92x10^{27}moleculesC_2F_4

Explanation:

Hello,

In this case, we use the Avogadro's number to compute the molecules of C2F4 whose molar mass is 100 g/mol contained in a 485-kg sample as shown below:

molecules=485kgC_2F_4*\frac{1000gC_2F_4}{1kgC_2F_4} *\frac{1molC_2F_4}{100gC_2F_4}*\frac{6.022x10^{23}molecules C_2F_4}{1molC_2F_4}  \\\\molecules=2.92x10^{27}moleculesC_2F_4

Best regards,

5 0
3 years ago
Which of the following information can be determined from this isotope: sodium 23 and why?
JulsSmile [24]

<h2>YOUR ANSWER Is number of istopes</h2>

✌️

4 0
3 years ago
How to find the value Of X, Y and Z​
Svetach [21]

Answer:

i might know you :)

Explanation:

6 0
3 years ago
3. If x electrons are needed to displace 108 g silver from a solution which contains Ag ions,
ss7ja [257]

Answer:

Choice A. x electrons would be required for displacing 9\; \rm g of aluminum from a solution of \rm Al^{3+} ions.

Assumption: by "\rm Ag ions" the question meant \rm Ag^{+} with a charge of +1 on each ion.

Explanation:

The question states that the relative atomic mass of \rm Ag is 108. In other words, each mole of

Therefore, that 108\; \rm g\! of silver that were formed would contain 1\; \rm mol of silver atoms.

Metallic silver would precipitate out of this \rm Ag^{+} solution only after these ions are turned into \rm Ag atoms.

One \rm Ag^{+} ion carries one unit of positive electrical charge. On the other hand, each  e^{-} carries one unit of negative electrical charge.

Therefore, each \rm Ag^{+}\! ion will need to gain one electron to form a neutral \rm Ag atom.

{\rm Ag^{+}}\; (aq) + e^{-} \to {\rm Ag}\; (s).

At least  1\; \rm mol of electrons would be required to turn 1\; \rm mol\! of \rm Ag^{+} ions into that 1\; \rm mol\!\! of silver atoms (which have a mass of 108\; \rm g\!.)

Hence, x = 1\; \rm mol.

Unlike \rm Ag^{+} ions, each aluminum ion \rm Al^{3+} carries three units of positive electrical charge. That is three times the amount of charge on one \rm Ag^{+}\! ion. Therefore, three electrons will be required to turn one \rm Al^{3+}\! ion to an \rm Al atom.

{\rm Al^{3+}}\; (aq) + 3\, e^{-} \to {\rm Al}\; (s)

The question states that the relative atomic mass of \rm Al is 27. Therefore, each mole of \rm Al\! atoms would have a mass 27\; \rm g. There would be \displaystyle \frac{9\; \rm g}{27\; \rm g \cdot mol^{-1}} = \frac{1}{3} \; \rm mol of atoms in that 9\; \rm g of \rm Al\!\!.

It takes 3\; \rm mol of electrons to turn one mole of \rm Al^{3+} ions to one mole of \rm Al atoms. Hence, \displaystyle \frac{1}{3}\times 3\; \rm mol = 1\; \rm mol of electrons would be required to produce that \displaystyle \frac{1}{3}\; \rm mol of \rm Al\! atoms (which has a mass of 9\; \rm g) from \rm Al^{3+}\! ions.

That corresponds to the first choice, x electrons.

7 0
3 years ago
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