C2H6O + 3O2 —> 2CO2 + 3H2O
Answer: Sulfuric acid, H2SO4, can be neutralized by sodium hydroxide, NaOH. The unbalanced equation is:
H2SO4(aq) + NaOH(aq) → Na2SO4(aq) + H2O(l)
A student who was asked to balance the reaction wrote the following:
H2SO4(aq) + Na2OH(aq) →Na2SO4(aq) + H3O(l)
Is this correct? Explain why or why not using what you know about the law of conservation of mass and chemical changes. If necessary, provide the correct balanced equation.
Explanation: The mass of the reactants must equal that of the products. This is because the masses of the products arise from the reactants and no mass is either created or destroyed. The total mass of the reactant must equal that of the product side and vice versa.
The student made an error of protonating the water molecule to H3O+ without a corresponding balance on the reactant side. In this case, it is wrong and ceases to be an equation. The product side masses don't equal the reactant side.
Balancing a chemical equation is done by first writing the correct chemical symbol. The moles and masses of each compound are cross-checked that they are equal on both sides of the equation.
The mass of NaCl sample has been 24.3 g. Thus, option A is correct.
The heat of fusion has been the amount of heat required to convert 1 mole of substance into solid to liquid state.
The heat required has been given as:
<h3>Computation for the mass of NaCl</h3>
The given solution has heat of fusion, 
The heat required to melt the sample has been, 
Substituting the values for the mass of NaCl
The mass of NaCl sample has been 24.3 g. Thus, option A is correct.
Learn more about heat of fusion, here:
brainly.com/question/87248
Answer: arrangement of constituent particles makes glass diff. from quartz. Glass-short range order of particles.
Quartz-Long range of particles.
If quartz is heated and cooled rapidly it can be converted to glass.
This reaction is called the electrolysis of water. The balanced reaction is:
2H2O = 2H2 + O2
We are given the amount of O2 produced from the electrolysis reaction. This will be the starting point of our calculation.
50.00 grams O2 ( 1 mol O2 / 32 grams O2) ( 2 mol H2O / 1 mol O2) ( 18.01 g H2O / 1 mol H2O ) = 56.28 g H2O
