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3 years ago

A fan is connected to a battery in a series circuit. What kind of energy transfer occurs if the circuit is closed?

Chemistry

1 answer:

True [87]3 years ago

8 0

Chemical to electrical energy

Explanation:

The kind of energy conversion that occurs in the closed circuit of a cell is from chemical to electrical energy.

A battery is an electromotive cell that stores chemical energy.

The chemical energy in a battery is a potential energy.
Chemical reactions takes place in electrochemical cells through chemical reactions to produce an electric current.
The reaction is a spontaneous redox reaction in which electric current flows on its own in the external circuit.

Learn more:

Electric circuit brainly.com/question/8892837

#learnwithBrainly

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Imagine that the apparent weight of the crown in water is <img src="https://tex.z-dn.net/?f=W_%7Bapparent%7D" id="TexFormula1" t

Ahat [919]

Answer : The crown is not made of pure (100%) gold.

Explanation :

Formula used :

$\frac{W_{apparent}}{W_{actual}}=1-\frac{\rho_w}{\rho_c}$

where,

$W_{apparent}$ = apparent weight of the crown in water = 4.50 N

$W_{actual}$ = actual weight = 5.00 N

$\rho_w$ = density of water = $1.00g/cm^3$

$\rho_c$ = density of crown = ?

Now put all the given values in the above formula, we get:

$\frac{4.50N}{5.00N}=1-\frac{1.00g/cm^3}{\rho_c}$

$\rho_c=10g/cm^3$

Density of crown < Density of gold

$10g/cm^3$

Thus, the crown is not made of pure (100%) gold.

5 0

4 years ago

FREE 60 points & maybe one brain liest!!!!!!

Rudiy27

Answer:

THANKS SO MUCH

I actually did the same thin last week

Explanation:

4 0

3 years ago

Read 2 more answers

Which mammal below lays tough leathery eggs? A) bear (placental) B) duck-billed platypus (monotreme) C) kangaroo (marsupial) D)

PolarNik [594]

Answer:

the answer to your question is B) Monotreme.

Explanation:

most mammals do not lay eggs, they give birth. But, monotreme mammals including the duck-billed platypus do in fact lay shelled eggs.

7 0

3 years ago

Read 2 more answers

A solution contains 0.0440 M Ca2 and 0.0940 M Ag. If solid Na3PO4 is added to this mixture, which of the phosphate species would

Olenka [21]

Answer:

C. $Ca_3(PO_4)_2$ will precipitate out first

the percentage of $Ca^{2+}$ remaining = 12.86%

Explanation:

Given that:

A solution contains:

$[Ca^{2+}] = 0.0440 \ M$

$[Ag^+] = 0.0940 \ M$

From the list of options , Let find the dissociation of $Ag_3PO_4$

$Ag_3PO_4 \to Ag^{3+} + PO_4^{3-}$

where;

Solubility product constant Ksp of $Ag_3PO_4$ is $8.89 \times 10^{-17}$

Thus;

$Ksp = [Ag^+]^3[PO_4^{3-}]$

replacing the known values in order to determine the unknown ; we have :

$8.89 \times 10 ^{-17} = (0.0940)^3[PO_4^{3-}]$

$\dfrac{8.89 \times 10 ^{-17}}{(0.0940)^3} = [PO_4^{3-}]$

$[PO_4^{3-}] =\dfrac{8.89 \times 10 ^{-17}}{(0.0940)^3}$

$[PO_4^{3-}] =1.07 \times 10^{-13}$

The dissociation of $Ca_3(PO_4)_2$

The solubility product constant of $Ca_3(PO_4)_2$ is $2.07 \times 10^{-32}$

The dissociation of $Ca_3(PO_4)_2$ is :

$Ca_3(PO_4)_2 \to 3Ca^{2+} + 2 PO_{4}^{3-}$

Thus;

$Ksp = [Ca^{2+}]^3 [PO_4^{3-}]^2$

$2.07 \times 10^{-33} = (0.0440)^3 [PO_4^{3-}]^2$

$\dfrac{2.07 \times 10^{-33} }{(0.0440)^3}= [PO_4^{3-}]^2$

$[PO_4^{3-}]^2 = \dfrac{2.07 \times 10^{-33} }{(0.0440)^3}$

$[PO_4^{3-}]^2 = 2.43 \times 10^{-29}$

$[PO_4^{3-}] = \sqrt{2.43 \times 10^{-29}$

$[PO_4^{3-}] =4.93 \times 10^{-15}$

Thus; the phosphate anion needed for precipitation is smaller i.e $4.93 \times 10^{-15}$ in $Ca_3(PO_4)_2$ than in $Ag_3PO_4$ $1.07 \times 10^{-13}$

Therefore:

$Ca_3(PO_4)_2$ will precipitate out first

To determine the concentration of $[Ca^+]$ when the second cation starts to precipitate ; we have :

$Ksp = [Ca^{2+}]^3 [PO_4^{3-}]^2$

$2.07 \times 10^{-33} = [Ca^{2+}]^3 (1.07 \times 10^{-13})^2$

$[Ca^{2+}]^3 = \dfrac{2.07 \times 10^{-33} }{(1.07 \times 10^{-13})^2}$

$[Ca^{2+}]^3 =1.808 \times 10^{-7}$

$[Ca^{2+}] =\sqrt[3]{1.808 \times 10^{-7}}$

$[Ca^{2+}] =0.00566$

This implies that when the second cation starts to precipitate ; the concentration of $[Ca^{2+}]$ in the solution is 0.00566

Therefore;

the percentage of $Ca^{2+}$ remaining = concentration remaining/initial concentration × 100%

the percentage of $Ca^{2+}$ remaining = 0.00566/0.0440 × 100%

the percentage of $Ca^{2+}$ remaining = 0.1286 × 100%

the percentage of $Ca^{2+}$ remaining = 12.86%

5 0

4 years ago

In matter results in a change in its identity and properties.

FrozenT [24]

Answer:

The chemical change in matter is results in a change in its identity and properties.

Explanation:

There are toe type of changes physical change and chemical change.

The chemical change change in matter lead to lost its identity and properties.

Chemical change:

The changes, that occur due to change in the composition of a substance and result in a different compound is known as chemical change.

These changes are irreversible

These changes occur due to chemical reactions

These may not be observed with naked eye

Example:

Combustion of fuel or wood: that oil or wood convert into energy, CO2 and ash in case of wood

Boiling of egg: that change the chemical composition of protein in the egg .

The reaction of Hydrogen and oxygen:

H 2 (g) + O 2 (g) -------------------------------------> 2H 2O (l)

7 0

4 years ago