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allochka39001 [22]
3 years ago
14

Find the value of x. 105 67

Mathematics
1 answer:
kodGreya [7K]3 years ago
6 0

Answer:

38

Step-by-step explanation:

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NEED ANSWER ASAP- FOR FINALS
blagie [28]

Answer:

Width - 12ft  Length - 30ft

Step-by-step explanation:

Width is 12ft

Length is 30ft

Depth is 6ft

The length, 30ft, is 2.5 times longer than the width which is 12 ft which confirms the two dimensions to be correct.

When you multiply all three of the dimensions of the swimming pool you will get 2940 cubic feet

8 0
3 years ago
Am I correct? Please correct me if I'm wrong
laiz [17]

Answer:

Great job

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
1. Given points A(3, -5) and B(19, -1), find the coordinates of point C that sit 3/8 of the way along line AB, closer to A than
zaharov [31]

1. C(x, y) = (7.3, –3.9)

2. C(x, y) = (17, –1.5)

Solution:

Question 1:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction \frac{3}{8}.

Point divides segment in the ratio formula:

$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)

Here, x_1=3, y_1=-5, x_2=19, y_2=-1 and m = 3, n = 8

$C(x, y)=\left(\frac{3\times19+8\times3}{3+8} , \frac{3\times(-1)+8\times(-5)}{3+8}\right)

           $=\left(\frac{57+24}{11} , \frac{-3-40}{11}\right)

           $=\left(\frac{81}{11} , \frac{-43}{11}\right)

C(x, y) = (7.3, –3.9)

Question 2:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction \frac{3}{8}.

Point divides segment in the ratio formula:

$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)

Here, x_1=3, y_1=-5, x_2=19, y_2=-1 and m = 7, n = 1

$C(x, y)=\left(\frac{7\times19+1\times3}{7+1} , \frac{7\times(-1)+1\times(-5)}{7+1}\right)

           $=\left(\frac{133+3}{8} , \frac{-7-5}{8}\right)

           $=\left(\frac{136}{8} , \frac{-12}{8}\right)

C(x, y) = (17, –1.5)

8 0
3 years ago
Plz answer this now anyone
bearhunter [10]

answer is f hope u like it plz mark me as brainliest plzzzzzzzzzzzzz

5 0
3 years ago
In any circle of radius R, how many arcs with lengths R fit into the circumference?
xenn [34]

<h2>~<u>Solution</u> :-</h2>

If we take the radius of a circle be <u>R</u>. Then, we can define that,

$ R = x $

Hence,

Arcs will be as $ 4x $. As,

A circle can be divided into four parts according to the radius.

Hence, we know that,

x \times 4

\mapsto \: 4x

  • Hence, <em>according to the radius R</em>, a circle can have <u>4 arcs</u>.
7 0
3 years ago
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