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3 years ago

HELP PLEASE 18 POINTS

Mathematics

1 answer:

ICE Princess25 [194]3 years ago

6 0

Answer:

Step-by-step explanation:

line 1 m=y2-y1 / x2-x1 [formula for slope ]

m= 0 - (-3) / 8-(-4)

m= 3 /12

m= 1/4 slope of line 1

line2

m = 2-6 / 0-(-1)

m = -4 / 1

m = -4 slope of line 2

line 3

m = -4 - (-7) / -3 - 6

m = 3 / -9

m = - 1/3 slope of line 3

lines 1 & 2 perpendicular b/c they are reciprocals with a sign change :)

lines 1 & 3 neither.. differet slopes and not reciprocals

lines 2 & 3 perpendicular b/c they are reciprocals with a sign change :)

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Answer:

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Step-by-step explanation:

change the underminator, we have

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3 years ago

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Answer:

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3 years ago

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4 years ago

A supplier of heavy construction equipment has found that new customers are normally obtained through customer requests for a sa

ziro4ka [17]

Answer:

The probability that it will take fewer than six customer contacts to clear the inventory is 0.8%.

Step-by-step explanation:

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We have 4 units, so the probability of clearing the inventory with n clients can be calculated as:

$P=\dbinom{n}{4}p^4q^{n-4}=\dbinom{n}{4}0.15^4\cdot 0.85^{n-4}$

As we see in the equation, n has to be equal or big than 4.

In this problem we have to calculate the probability that less than 6 clients are needed to sell the 4 units.

This probability can be calculated adding the probability from n=4 to n=6:

$P=\sum_{n=4}^6P(n)=\sum_{n=4}^6 \dbinom{n}{4}0.15^4^\cdot 0.85^{n-4}\\\\\\P=0.15^4(\dfrac{4!}{4!0!}\cdot 0.85^{4-4}+\dfrac{5!}{4!1!}\cdot0.85^{5-4}+\dfrac{6!}{4!2!}0.85^{6-4})\\\\\\P=0.15^4(1\cdot0.85^0+5\cdot0.85^1+15\cdot0.85^2)\\\\\\P=0.00051(1+4.25+10.84)\\\\\\P=0.00051\cdot16.09\\\\\\P=0.008$

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3 years ago