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2 years ago

If x^2 + 1/x^2 = 98 find x + 1/x

1 answer:

5 0

Given,

x
2
+
x
2

1

=98

(x+
x
1

)
2
=x
2
+
x
2

1

+2

98+2=100

∴x+
x
1

=10

(x+
x
1

)
3
=x
3
+
x
3

1

+3(x+
x
1

)

x
3
+
x
3

1

+3(x+
x
1

)=1000

x
3
+
x
3

1

=1000−3(10)=

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If y represents a number, write an expression that represents the sum of y and a number one greater than y

Dimas [21]

Answer:

2y+1=0

Step-by-step explanation:

a number one greater than y is y+1

so sum of y and y+1= 2y+1

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3 years ago

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SHOW YOUR WORK, <br><br>PLEASE HELP!!!!!!!!!

Shkiper50 [21]

To find the inverse, we swap the variables y and x, then solve for the new y.

3a. $y=\frac{3}{x-1}$

Swapping the variables: $x=\frac{3}{y-1}$
Solving for y: $x(y-1)=3 \\ y-1= \frac{3}{x} \\ y=1+\frac{3}{x}$
The domain of this inverse is $x ≠ 0$ .
3b. $y=x^2-1$

Swapping: $x = y^2 - 1$
Solving for y: $y^2 = x + 1 \\ y = \sqrt{x+1}$
The domain of this inverse is $x ≥ -1$ .
3c. $y=\sqrt[3]{\frac{x-7}{3}}$
Swapping: $x=\sqrt[3]{\frac{y-7}{3}}$
Solving for y: $x^3=\frac{y-7}{3} \\ y-7=3x^3 \\ y=3x^3+7$
The domain of this inverse is all real numbers.
4a. $y=\frac{3}{x-1}$ , $y=1+\frac{3}{x}$
$y=\frac{3}{(1+\frac{3}{x})-1} \\ y=\frac{3}{(\frac{3}{x})} \\ y=x$
$y=1+\frac{3}{(\frac{3}{x-1})} \\ y = 1+(x-1) \\ y = x$

4c. $y=\sqrt[3]{\frac{x-7}{3}}$ , $y=3x^3+7$
$y=\sqrt[3]{\frac{(3x^3+7)-7}{3}} \\ y=\sqrt[3]{\frac{3x^3}{3}} \\ y=\sqrt[3]{x^3} \\ y=x$
$y=3(\sqrt[3]{\frac{x-7}{3}})^3+7 \\ y = 3({\frac{x-7}{3}})+7 \\ y = (x-7)+7 \\ y=x$

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3 years ago

Amy sold 338 flowers at the market today. If each bunch has 13 flowers in it, how many bunches did Amy sell?

Lady_Fox [76]

Answer:

Step-by-step explanation:

338 / 13 = 26

26 batches of 13 flowers are equal to 338.

8 0

2 years ago

One-third of the result of three times a number that is increased by 12

SashulF [63]

Answer:

(1/3)(3x+12)

Step-by-step explanation:

1/3

times (3x+12)

3x+12 will be three times the number x + 12

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3 years ago

The Question Is:

lora16 [44]

Answer:

C) ∠3 and ∠6 is the CORRECT OPTION.

Step-by-step explanation:

Here, the image is UNATTACHED. Attaching image here for the reference.

Given: JL and MP are parallel.

Alternate Interior angles is a pair of angles formed when there is a common intersecting line between two parallel lines.

As JL and MP are parallel.

and KN is a traversal. So, the pair of Alternate Interior angles so formed are:

a) ∠3 and ∠6

b) ∠4 and ∠5

Now, out of the given options:

A. ∠3 and ∠4 is a LINEAR PAIR

B. ∠1 and ∠6 makes no pair

C. ∠3 and ∠ 6 is a Alternate Interior angles pair

D. ∠5 and ∠6 LINEAR PAIR

Hence, ∠3 and ∠ 6 is a Alternate Interior angles pair.

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3 years ago

If x^2 + 1/x^2 = 98 find x + 1/x​

If x^2 + 1/x^2 = 98 find x + 1/x