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Sphinxa [80]
2 years ago
12

If x^2 + 1/x^2 = 98 find x + 1/x​

Mathematics
1 answer:
Pavel [41]2 years ago
5 0
Given,

x
2
+
x
2

1
​
=98

(x+
x
1
​
)
2
=x
2
+
x
2

1
​
+2

98+2=100

∴x+
x
1
​
=10

(x+
x
1
​
)
3
=x
3
+
x
3

1
​
+3(x+
x
1
​
)

x
3
+
x
3

1
​
+3(x+
x
1
​
)=1000

x
3
+
x
3

1
​
=1000−3(10)=
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A meteorologist reports that the ration of snowfall in January to total snowfall during the average winter is 2 to 5. If 34 inch
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Answer:

13.6 inches.

Step-by-step explanation:

First do 2/5 = x/34, then multiply 34 by 2 and you get 68, then 68 divided by 5 is 13.6!

Hope this helped!

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3 years ago
Part A: Clancey and Ethan are starting new books. So far, Clancey has read 1/4 of his book, which has 240 total pages and Ethan
Nonamiya [84]

In order to find who has read more pages, let's find the number of pages read by each one.

The number of pages read by Clancey is:

\frac{1}{4}\cdot240=\frac{240}{4}=60

The number of pages read by Ethan is:

\frac{2}{5}\cdot170=\frac{340}{5}=68

So Ethan read more pages.

The combined number of pages in both books is 240 + 170 = 410.

The combined number of pages read is 60 + 68 = 128

So the fraction is:

\frac{128}{410}=\frac{64}{205}

5 0
1 year ago
Can someone help me please.
slega [8]
6^log(216) is the answer
5 0
3 years ago
Michael is using a drawing program to complete a construction. Which construction is he completing? A circle is drawn with two p
Varvara68 [4.7K]
The drawing shows a circle, with the two lines forming a cross assumed to be perpendicular to each other, so this is most likely to be a square, as the four points at which the perpendicular lines intersect with the circle can be connected to form a square.
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3 0
3 years ago
Read 2 more answers
Pleaseee helppp with thissss asapppp
Natasha2012 [34]

As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0
1 year ago
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