Answer:
Step-by-step explanation:
it's going to alternate back and froth between positive and negative, maybe it will make one of those "telescoping" sequences
The area of the figure is 26 square units. There is 6 of a 2 which adds up 12 and there is one 8 and adding it with 12 would be 20. The last number was a 6 so you add 20 with 6 which adds up of 26 square units. So the area Of the firgure is 26 square units.
To solve this problem yo need to have the "x", the "y", and the radius. To find the radius since it is not given we use the formula.
sq rt(-3^2+1^2)
sq rt(9+1)
sq rt(10) would be the length of the radius in this case.
Then we use the sine cosine and tangent fractions
sin:y/r
cos:x/r
tan:y/x
With the values plugged in the equations are
SIN:1/sqrt(10) Since there can´t be a sq rt in hte denominator we change it to 1(sq rt(10))/10
COS:-3/sqrt(10) Since there can´t be a sq rt in the denominator we change it to -3(sq rt(10))/10
TAN:1/-3 This one can stay the same.
This would be the measures of SIN, COS, and TAN.
You have to make them have their least common denominator to add or subtract, in this case 36.
Multiply 1/12 by 3, to get the denominator 36: 3/36.
Multiply 7/9 by 4, to get the denominator 36: 28/36.
Now add the numerators: 3+28=31, 31/36 is as simplified as possible so your answer is 31/36 :) I hope this helps :)
