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mihalych1998 [28]

3 years ago

11

the average rate of change of the function f(x) on the interval -3≤x≤3 is -2.5. If (-3)=14 then which of the following is the va

lue of f(3)?

1 answer:

oksian1 [2.3K]3 years ago

4 0

The average rate of change of <em>f(x)</em> on -3 ≤ <em>x</em> ≤ 3 is given to be

(<em>f</em> (3) - <em>f</em> (-3)) / (3 - (-3)) = -2.5

If <em>f</em> (-3) = 14, then

(<em>f</em> (3) - 14) / (3 + 3) = -2.5

(<em>f</em> (3) - 14) / 6 = -2.5

<em>f</em> (3) - 14 = -15

<em>f</em> (3) = -1

You might be interested in

Which equation is the slope-intercept form of the line that passes through (-3,5) and is parallel to the of y=−2\3x+5

irinina [24]

Answer:

y = -2/3x + 3

Step-by-step explanation:

y = -2/3x + b

5 = -2/3(-3) + b

5 = 2 + b

3 = b

8 0

2 years ago

Calculate the mean number of students per class at watch school. Write your answers in sentences that explain what the means rep

Tpy6a [65]

To find the mean you add all the numbers then divide the sum by how many numbers there are :

1)Ford School

21+19+20=60

there are 3 numbers in the equation so you divide 60 by 3 :

60÷3=20

the mean for Ford School is 20

2)Carter School

41+36+37=114

there are 3 numbers in the equation so you divide 114 by 3 :

114÷3=38

the mean for Carter School is 38

hope this helps

6 0

2 years ago

Read 2 more answers

The polygon Q(3, 2), R(6,5), S(6, 2)

ycow [4]

Answer:

Q' (12,8) , R'( 24,20) and S' (24,8)

Step-by-step explanation:

Here, we want to get the coordinates of the image after dilating the pre-image by a scale factor of 4

What we have to do here is to multiply each of the coordinate on the pre-image by 4

We have this as;

Q' = (4*3, 2 * 4) = (12,8)

R' = (4*6, 4*5) = (24,20)

s' = (4*6, 4*2) = (24,8)

4 0

3 years ago

Use the Parabola tool to graph the quadratic function. f(x)=2x^2−12x+19 Graph the parabola by first plotting its vertex and then

Debora [2.8K]

To find the vertex of our parabola, we are going to use the vertex formula: For a quadratic of the form $f(x)=x^2+bx+c$ it vertex $(h,k)$ is given by $h= \frac{-b}{2a}$ , $k=f(h)$ .
We can infet from our parabola that $a=2$ and $b=-12$ . So lets replace those values in our formula:
$h= \frac{-b}{2a}$
$h= \frac{-(-12)}{2(2)}$
$h= \frac{12}{4}$
$h=3$
$k=f(h)=2(3)^2-12(3)+19$
$k=2(9)-36+19$
$k=18-17$
$k=1$
The vertex $(h,k)$ of our parabola is $(3,1)$

Now to find our second point, we are going to evaluate our parabola at $x=0$
$f(0)=2(0)^2-12(0)+19$
$f(0)=0+0+19$
$f(0)=19$
Our second point is $(0,19)$

We can conclude that we can graph the parabola $f(x)=2x^2-12x+19$ using its vertex $(3,1)$ and the point $(0,19)$ as follows:

7 0

3 years ago

This is my my second to <br>last one, thanks for helping me

icang [17]

9514 1404 393

Answer:

$9
Option 4

Step-by-step explanation:

The equations need to match the problem statements. If we let C and S represent the costs of Cherry and Sweet potato pies, respectively, then the revenue from each sale can be expressed as an equation.

1 cherry and 7 sweet potato for $114 ⇒ C +7S = 114

14 sweet potato and 11 cherry for $309 ⇒ 11C +14S = 309

Note that we have used C and S in the second equation in the same order as they appeared in the first equation, even though the problem statement has that order reversed. This facilitates solving the equations using elimination or Cramer's rule.

These equations match Option 4.

__

The cost of a cherry pie can be found by eliminating S from the equations. We can do that by subtracting twice the first equation from the second:

(11C +14S) -2(C +7S) = (309) -2(114)

9C = 81 . . . . . simplify

C = 9 . . . . . . . divide by 9

The cost of each cherry pie is $9.

3 0

3 years ago